在Python中使用__init__和继承

Question

I'm a little confused regarding using __init__ and inheritance and would love to get some help with it.

I have a class [that can not be changed]:

class A(object):
    def __init__(self, param1 = 7, param2 = 10):
        self.x = param1
        self.y = param2     
    def func1(self):
        op1()
        op2()
    def func2(self):
        pass

this is some class that was written and I'm using it when overloading its functions:

class B(A):
    def func1(self)
        op3()
        op4()
    def func2(self)
        op5()

My problem starts here : I want to use Class B several times and sent each time different parameter:

---new .py file: ---
def myFunction():
    myInstance = B()

I want to do something like :

def myFunction():
    myInstance = B(40,"test")

I thought adding to B class - __init__ but the problem is that now I'm not sure what self it would use : explanation : Inside B class I have overloaded func2(self) I thought writing :

class B(A):
    def __init__(self, paramNumber, paramString)
        self.paramNumber = paramNumber
        self.paramString = paramString

but now in func2(self) , what self is used? the new one? the old one? will it work? meaning I will have : self.x , self.y and self.paramNumber self.parmString ? they are different "selfs"

Editing : Should I use super as well?

    class B(A):
    def __init__(self, paramNumber, paramString,param1, param2)
        self.paramNumber = paramNumber
        self.paramString = paramString
        super(B,self).__init__(param1,param2)

    def myFunction():
       myInstance = B(40,"test")
       // I will get : self.x = 7
       // self.y= 10
       // self.paramNumber=40
       //self.paramString = "test"

is this the correct solution?

Answer 1

So basically you want to run __init__ from parent class inside child:

class B(A):
    def __init__(self, paramNumber, paramString):
        super(B, self).__init__(param1=1, param2=2)
        # the other code goes here