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在Java中将JsonString解析为JsonObject

[英]Parse JsonString to JsonObject in Java

I have the following String : 我有以下字符串:

{
    "response": true,
    "model_original_id": "5acea0b5:1431fde5d6e:-7fff",
    "model_new_id": 500568,
    "model_new_version": 1,
    "reload": true,
    "idsModelProperties": [{
        "key": "creation_date",
        "value": "2013-12-23"
    },
    {
        "key": "state",
        "value": 1,
        "displayValue": "Analisi"
    }],
    "idsNodes": [],
    "idsConnectors": [],
    "idsNodesProperties": []
}

and i need to parse it as a JSONObject. 我需要将其解析为JSONObject。 I tried to use quickjson but it gives me an exception when it tries to parse an emty string . 我试图使用quickjson但它在尝试解析一个emty字符串时给了我一个例外。 This is what i tried : 这是我试过的:

JsonParserFactory factory=JsonParserFactory.getInstance();
JSONParser parser=factory.newJsonParser();
Map jsonData=parser.parseJson(response_output);

Exception: Exception in thread "main" com.json.exceptions.JSONParsingException: @Key-Hierarchy::root/idsNodes[0]/ @Key:: Value is expected but found empty...@Position::256 异常: 线程“main”中的异常com.json.exceptions.JSONParsingException:@ Key-Hierarchy :: root / idsNodes [0] / @Key ::值是预期的,但是找到空... @ Position :: 256

Any idea? 任何的想法?

I'll give you an alternative since it looks like quick-json has trouble parsing empty json arrays. 我会给你一个替代方案,因为它看起来像quick-json在解析空的json数组时遇到了麻烦。 Check out Gson . 看看Gson

String json = "{ \"response\": true, \"model_original_id\": \"5acea0b5:1431fde5d6e:-7fff\", \"model_new_id\": 500568, \"model_new_version\": 1, \"reload\": true, \"idsModelProperties\": [{ \"key\": \"creation_date\", \"value\": \"2013-12-23\" }, { \"key\": \"state\", \"value\": 1, \"displayValue\": \"Analisi\" }], \"idsNodes\": [], \"idsConnectors\": [], \"idsNodesProperties\": []}";
JsonParser jsonParser = new JsonParser();
JsonElement jsonElement = jsonParser.parse(json);

JsonElement is an abstract class. JsonElement是一个抽象类。 Its sub types are JsonArray , JsonNull , JsonObject and JsonPrimitive . 它的子类型是JsonArrayJsonNullJsonObjectJsonPrimitive In the example above, the actual instance is a JsonObject because your json String is a json object. 在上面的示例中,实际的实例是JsonObject因为您的json String是一个json对象。 It internally contains a LinkedTreeMap but you don't really need access to it. 它内部包含一个LinkedTreeMap但您实际上并不需要访问它。 You can access the different json objects directly on the JsonElement . 您可以直接在JsonElement上访问不同的json对象。

While the author of the question has already accepted an answer, someone else might be searching for the same issue. 虽然问题的作者已经接受了答案,但其他人可能正在搜索相同的问题。 I've fixed the issues I know of with quick-json in https://code.google.com/p/quick-json/issues/detail?id=11 我在https://code.google.com/p/quick-json/issues/detail?id=11中使用quick-json解决了我所知道的问题

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