在android中聊天应用程序，以便发送者和接收者消息应该在不同的一面

Question

 protected void onPostExecute( ArrayList<HashMap<String,String>> myArrayList)//    for arraylist(ArrayList<String> result)
   {                            

       for (HashMap<String, String> data : myArrayList)
      {
           String sender_no = data.get(TAG_SENDER_NO);
           String msg1=data.get(TAG_SEN_MSG);
           String receiver_no=data.get(TAG_RECEIVER_NO);

           if(sender_no.equals(senderno))
           {

           ListAdapter adapter = new SimpleAdapter(SinglechatActivity.this, myArrayList,R.layout.list_row_layout_even, 
           new String[] { TAG_SEN_MSG },new int[] { R.id.message_me });

        //  CustomList adapter= new CustomList(SinglechatActivity.this,myArrayList);//sender_no,  msg1,   receiver_no);

         ListView  lv = (ListView) findViewById(R.id.listview);
           lv.setAdapter( adapter);

          }

           else

           {
               ListAdapter adapter = new SimpleAdapter(SinglechatActivity.this, myArrayList,R.layout.list_row_layout_odd, 
                       new String[] { TAG_SEN_MSG },new int[] { R.id.message_frnd });

                //  CustomList adapter= new CustomList(SinglechatActivity.this,  sender_no,  msg1,   receiver_no);

                 ListView  lv = (ListView) findViewById(R.id.listview);
                   lv.setAdapter( adapter);

           }

In this, I would like to have message on right hand side and left hand side based on the sender and receiver.

Answer 1

Use Custom adapter with separate layouts for sender and receiver messages. It is called Heterogeneous ListView .

Something like this

public class MyAdapter extends BaseAdapter {

    ArrayList<HashMap<String,String>> messages;
    int SENDER_MESSAGE = 0;
    int RECEIVER_MESSAGE = 1;
    Context context;

    @Override
    public int getCount() {
        return messages.size();
    }

    @Override
    public Object getItem(int position) {
        return messages.get(position);
    }

    @Override
    public long getItemId(int position) {
        return position;
    }

    @Override
    public int getViewTypeCount() {
        return 2;
    }

    @Override
    public int getItemViewType(int position) {

        //This is dummy logic
        //Write your own logic to differentiate between sender and receiver message
        if (position % 2 == 0) {
            return SENDER_MESSAGE;
        }

        else {
            return RECEIVER_MESSAGE;
        }
    }

    @Override
    public View getView(int position, View convertView, ViewGroup parent) {

        if (convertView == null) {
            LayoutInflater inflater = (LayoutInflater) context.getSystemService(Context.LAYOUT_INFLATER_SERVICE);

            if (getItemViewType(position) == SENDER_MESSAGE) {
                convertView = inflater.inflate(R.layout.sender_message_layout, null);
            } 

            else {
                //Received message
                convertView = inflater.inflate(R.layout.received_message_layout, null);
            }
        }

            //...set text to message layout here


    }



}

For more info on Custom Adapter you can refer this

http://www.vogella.com/articles/AndroidListView/article.html#adapterown_example

For heterogeneous ListView (Different row layouts in ListView) tutorial you can refer this

http://chrislee.kr/wp/tag/getitemviewtype-tutorial/

Answer 2

In your onBindViewHolder() method of your recyclerView adapter you can align the sender or receiver view layout programatically using an "if" statement. For example if it is sender align left or right, etc Use the code below for example to access and set the view layout parameters:

 RelativeLayout.LayoutParams params = 
 (RelativeLayout.LayoutParams)button.getLayoutParams();
 params.addRule(RelativeLayout.ALIGN_PARENT_RIGHT);
 params.addRule(RelativeLayout.LEFT_OF, R.id.id_to_be_left_of);
 button.setLayoutParams(params);