如何检索Android手机的“联系人”列表中的“ ME”联系人详细信息

Question

I am developing an app,which will use phoneOwner details(like name, phoneNo, Email Id etc) which is coming under "ME" header of Contact List. Is there any way to get all these details?

Answer 1

This code will retrive all contactDetails of all contact Inside ContactList

public class MainActivity extends Activity {
    TextView textDetail;

    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);
        textDetail = (TextView) findViewById(R.id.textView1);
        readContacts();
    }

    public void readContacts() {

        StringBuffer sb = new StringBuffer();

        sb.append("your contacts");

        ContentResolver content = getContentResolver();

        Cursor c = content.query(ContactsContract.Contacts.CONTENT_URI, null,null, null, null);
        String phone = null;
        String emailContact = null;
        String emailType = null;
                String name = null;

        if (c.getCount() > 0) {

            while (c.moveToNext()) {

                String id = c.getString(c.getColumnIndex(ContactsContract.Contacts._ID));

                    name = c.getString(c.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME));

                if (Integer.parseInt(c.getString(c
                                .getColumnIndex(ContactsContract.Contacts.HAS_PHONE_NUMBER))) > 0) {

                    System.out.println("ContactName : " + name + ", ID : " + id);

                    sb.append("\n Contact Name:" + name);

                    Cursor phoneno = content.query(
                            ContactsContract.CommonDataKinds.Phone.CONTENT_URI,
                            null,
                            ContactsContract.CommonDataKinds.Phone.CONTACT_ID
                                    + " = ?", new String[] { id }, null);

                    while (phoneno.moveToNext()) {
                        phone = phoneno.getString(phoneno.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));
                        sb.append("\n Phone number:" + phone);
                        System.out.println("phone" + phone);
                    }
                    phoneno.close();

                    Cursor emailid = content.query(
                            ContactsContract.CommonDataKinds.Email.CONTENT_URI,
                            null,
                            ContactsContract.CommonDataKinds.Email.CONTACT_ID
                                    + " = ?", new String[] { id }, null);

                    while (emailid.moveToNext()) {

                        emailContact = emailid.getString(emailid.getColumnIndex(ContactsContract.CommonDataKinds.Email.DATA));
                        emailType = emailid.getString(emailid.getColumnIndex(ContactsContract.CommonDataKinds.Email.TYPE));

                        sb.append("\nEmail:" + emailContact + "Email type:"
                                + emailType);
                        System.out.println("Email " + emailContact
                                + " Email Type : " + emailType);
                    }
                    emailid.close();
                }

                sb.append("\n");
                sb.append("Next");
            }
            textDetail.setText(sb);
        }
    }
}

To retrive only one contact add line as below,

if(name.equals("ME"){

// whatever you want to do
}

It will display only that contact detail..

Answer 2

Cursor c = activity.getContentResolver().query(
                    ContactsContract.Profile.CONTENT_URI, null,  null, null, null);
    int count = c.getCount();
    String[] columnNames = c.getColumnNames();
    c.moveToFirst();
    int position = c.getPosition();
    if (count == 1 && position == 0) {
        for (int i = 0; i < count; i++) {
            for (int j = 0; j < columnNames.length; j++) {
                String columnName = columnNames[j];
                System.out.println(">>"+columnName+" = "+cursorContacts.getString(cursorContacts.getColumnIndex(columnName)));
            }
           c.moveToNext();
        }
    }
    c.close();