仅将非空列表转换为列表列表中的元组

Question

how do i convert this:

[[], [], [('ef', 1)], [], [('cd', 3)], [('ab', 2)]]

into this:

[[], [], ['ef', 1], [], ['cd', 3], ['ab', 2]]

i understand that to convert a tuple into a list, we would simply use list(tuple), or if it is a list like [(1,2),(3,4)] we can use map. How would i do this with the tuples that are within a list that is inside the main list, while the empty lists remain unchanged?

Answer 1

>>> my_list = [[], [], [('ef', 1)], [], [('cd', 3)], [('ab', 2)]]

>>> [list(*el) for el in my_list]
[[], [], ['ef', 1], [], ['cd', 3], ['ab', 2]]

Answer 2

>>> l = [[], [], [('ef', 1)], [], [('cd', 3)], [('ab', 2)]]
>>> import itertools
>>> [list(itertools.chain(*item)) for item in l]
[[], [], ['ef', 1], [], ['cd', 3], ['ab', 2]]

This will also handle multiple tuples per list element (if that's what is desired):

>>> l = [[], [], [('ef', 1)], [], [('cd', 3),('ab', 2)]]
>>> [list(itertools.chain(*item)) for item in l]
[[], [], ['ef', 1], [], ['cd', 3, 'ab', 2]]

Answer 3

Something like this:

>>> lis = [[], [], [('ef', 1)], [], [('cd', 3)], [('ab', 2)]]
>>> [list(x[0]) if x else x for x in lis]
[[], [], ['ef', 1], [], ['cd', 3], ['ab', 2]]