Case Insensitive Python string split（）方法

Question

I have 2 strings

a = "abc feat. def"
b = "abc Feat. def"

I want to retrieve the string before the word feat. or Feat.

This is what I'm doing,

a.split("feat.", 1)[0].rstrip()

This returns abc . But how can I perform a case insensitive search using split delimiter?

This is what I've tried so far

b.split("feat." or "Feat.", 1)[0].rstrip()

Output - abc Feat. def abc Feat. def

b.split("feat." and "Feat.", 1)[0].rstrip()

Output - abc

a.split("feat." and "Feat.", 1)[0].rstrip()

Output - abc feat. def abc feat. def .

a.split("feat." or "Feat.", 1)[0].rstrip()

Output - abc

Why is this difference with and and or in both the cases?

Answer 1

Use a regex instead:

>>> import re
>>> regex = re.compile(r"\s*feat\.\s*", flags=re.I)
>>> regex.split("abc feat. def")
['abc', 'def']
>>> regex.split("abc Feat. def")
['abc', 'def']

or, if you don't want to allow FEAT. or fEAT. (which this regex would):

>>> regex = re.compile(r"\s*[Ff]eat\.\s*")

Answer 2

a[0:a.lower().find("feat.")].rstrip() would do.

and ing

"string1" and "string2" and ... and "stringN"

returns the the last string.

or ing

"string1" or "string2" or ... or "stringN"

would return the first string.

Short-circuit evaluation .

Answer 3

You should use regex:

re.split('\s*[Ff]eat\.', a)

and and or do some boolean judgement.

"feat." or "Feat." -> "feat." if "feat." else "Feat." -> "feat."

"feat." and "Feat." -> "Feat." if "feat." else "feat." -> "Feat."