Tomcat 异常 提交响应后无法调用 sendError()？

Question

While doing some operations in my application I got

java.lang.IllegalStateException Cannot call sendError()

When I reload the page again it work some time properly, but after some time again it shows the same exception. How can I overcome this exception?

Below is the exception:

HTTP Status 500 - Cannot call sendError() after the response has been committed
type Exception report
message Cannot call sendError() after the response has been committed
description The server encountered an internal error that prevented it from fulfilling this request.
exception 
java.lang.IllegalStateException: Cannot call sendError() after the response has been committed
org.apache.catalina.connector.ResponseFacade.sendError(ResponseFacade.java:451)
org.apache.struts2.dispatcher.Dispatcher.sendError(Dispatcher.java:725)
org.apache.struts2.dispatcher.Dispatcher.serviceAction(Dispatcher.java:485)
org.apache.struts2.dispatcher.FilterDispatcher.doFilter(FilterDispatcher.java:395)
note The full stack trace of the root cause is available in the Apache Tomcat/7.0.40 logs.

Struts.xml

<struts>
    <package name="default" extends="hibernate-default">
        <action name="addUser" method="add" class="com.demo.action.UserAction">
            <result name="input">/register.jsp</result>
            <result name="success" type="redirect">list</result>
        </action>
        <action name="list" method="list" class="com.demo.action.UserAction">
            <interceptor-ref name="basicStackHibernate" />
            <result name="success">/list.jsp</result>
        </action>
    </package>
</struts>

Answer 1

This error is a symptom of some other problem, not the root cause you're looking for.

This error explains why the user can't be redirected to the error page. (Reason: the server has already flushed part of the response buffer back to the client - it's too late to switch/redirect to the error page.)

As the error message points out, check elsewhere in your Apache Tomcat 7 logs (or debug your app another way) to find what is throwing an exception.

Answer 2

I was creating a @ManyToOne and @OneToMany relationship. I added @JsonIgnore above the @ManyToOne and it solved the error.

Answer 3

我通过将@jsonIgnore添加到另一个对象列表的所有 getter 来解决此错误

Answer 4

For others in my situation--What was happening was that I had two @Entity objects with a many to many relationship causing infinite json to be generated, causing spring security to throw this error. Try adding @JsonIgnore above your hibernate relationships.

Answer 5

Note: there are 2 @JsonIgnore dependencies you can import. Make sure it's from Jackson library; that made the difference for me:

import com.fasterxml.jackson.annotation.JsonIgnore;

Answer 6

This is a common error and there can be various root cause can be identified. In my case I were opening pdf file from the web service and for this I were performing write operation in file using buffer. So kindly change below:

        File outfile = File.createTempFile("temp", ".pdf");

        OutputStream os=new FileOutputStream(outfile);
        byte[] buffer = new byte[1024];

        int length;
        /*copying the contents from input stream to
         * output stream using read and write methods
         */
        while ((length = is.read(buffer)) > 0){
            os.write(buffer, 0, length);
        }

to

        File outfile = File.createTempFile("temp", ".pdf");
        IOUtils.copy(is, new FileOutputStream(outfile));

and after this I were performing below operation:

    javax.ws.rs.core.Response.ResponseBuilder responseBuilder = javax.ws.rs.core.Response
                .ok(outfile, MediaType.APPLICATION_OCTET_STREAM);
                responseBuilder.header("content-type","application/pdf");

             return responseBuilder.build();

and error get resolved. Cheers!

Answer 7

You can try this Annotation it will help as it fixed my issue.

It will definitely help if it will not be able to help you, then try to modify this as per your requirement.

@JsonIdentityInfo(generator=ObjectIdGenerators.PropertyGenerator.class, property="id")
   @JsonIdentityReference(alwaysAsId=true)

Answer 8

This is what caused it in my case.

I have 2 filters that both have the capability to send an error through the HttpServletResponse.sendError() method. If Filter A discovered something wrong and called sendError on the HttpServletResponse object, then a second call in the same filter or in filter B will cause the cannot call senderror exception. This is because sendError does not cause the request itself to be aborted. The code in the filter continues to be executed after the sendError method had been called.

Answer 9

在@ManyToOne 上方使用@JsonIgnore

Answer 10

if u use annotations like:@WebFilter,@WebServlet...,just add metadata-complete="true" into web.xml eg

<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
         xmlns="http://java.sun.com/xml/ns/javaee" 
         xmlns:web="http://java.sun.com/xml/ns/javaee" 
         xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" 
         id="WebApp_ID" metadata-complete="true" version="3.0">

Hope this is your need!

Answer 11

There are so many answers to use @JsonIgnore annotation. But I will not recommend it. If your parent class has a many-to-one relationship with single entity then it is fine. But if your parent class has two many-to-one relationships then definitely it gives a headache to you.

I will suggest going with a uni-directional approach and implement a separate dto class based on your requirement.

Answer 12

I was using Jersey and I returned the following response

Response.status(HttpStatus.SC_MOVED_TEMPORARILY).header("Location", "https://example.com?param1=foo bar").build()

After URL encoding, the issue was solved

Response.status(HttpStatus.SC_MOVED_TEMPORARILY).header("Location", "https://example.com?param1=foo%20bar").build()

Answer 13

Adding @JsonIgnore solved the current error. However, it cause error when creating entry of entity with @ManyToOne annotation.

Using @JsonBackReference(value = "**") (where ** is the property of the entity with @OneToMany annotation) can also solve this error while not causing other errors!

(in my case, Im using User object with @ManyToOne annotation, but Im using the id of User as a column in sql table)

Answer 14

@ManyToOne 映射上的 @JsonIgnore 将解决它。

Answer 15

I have overcome the exception,you may check your table structure.I execute the sql query produced by hibernate in mysql. As excepted，an exception was thrown.

[Err] 1054 - Unknown column 'this_.ID' in 'field list'

I found that a field ID is missing in the table.Add the ID into the table ,it's ok. Hope it's helpful.