用地址值初始化指针

Question

I need to initialize a pointer variable with a knowing address. Please see code below, ptr is the final destination and value of ptr_address contains the address value, so I need to do something like ptr = value.

int *ptr;
int address;

address = 0x10000005;
ptr = address;

The problem is that compiler gives the following warning message:

warning: assignment makes pointer from integer without a cast [enabled by default]

Is my code wrong or there is any other way to do it without receiving this compiler warning?

Answer 1

Use a cast:

intptr_t some_variable = 25;

int * ptr1 = (int *) 0x10000005;
int * ptr2 = (int *) some_variable;

Or in C++:

int * ptr1 = reinterpret_cast<int *>(0x10000005);
int * ptr2 = reinterpret_cast<int *>(some_variable);