[英]SQL Get entire row based on minimum value of calculated column
I have a table with multiple values of bed ID with different statuses, something like this. 我有一张桌子,床身ID有多个不同的状态,就像这样。
PID | term_id | student_id | bed_id | status | Comment
--------+------------+---------------+-----------+-----------+----------------
1 | 29 | 1234 | 751 | Canceled | Not this one
2 | 29 | 1234 | 751 | Active | This one
3 | 29 | 531 | 752 | Active | This one too
4 | 29 | 823 | 752 | Canceled | Not this one either
5 | 29 | 525 | 753 | Canceled | But this one too
I want a query to get a single row for each bed_id based on the value of status. 我想要一个查询,根据状态值为每个bed_id获取一行。
I've tried: 我试过了:
SELECT *,MIN(CASE sample.status
WHEN 'Arrived' THEN 1
WHEN 'Active' THEN 2
WHEN 'Pending Approval' THEN 3
WHEN 'Pending Confirmation' THEN 4
WHEN 'Pending Manual' THEN 5
WHEN 'Denied' THEN 6
WHEN 'Canceled' THEN 7
END) AS StatusOrder
FROM sample
WHERE (sample.term_id = 29)
GROUP BY bed_id
But it gives me: 但它给了我:
PID | term_id | student_id | bed_id | status | Comment | StatusOrder
------------------------------------------------------------------------------------
1 | 29 | 1234 | 751 | Canceled | Not this one | 2
3 | 29 | 531 | 752 | Active | This one too | 2
5 | 29 | 525 | 753 | Canceled | But this one too | 7
(The StatusOrder value is right, but the rest of the row does not correspond to the row with minimum StatusOrder value) (StatusOrder值是正确的,但行的其余部分与具有最小StatusOrder值的行不对应)
What I want is: 我想要的是:
PID | term_id | student_id | bed_id | status | Comment | StatusOrder
------------------------------------------------------------------------------------
2 | 29 | 1234 | 751 | Active | This one | 2
3 | 29 | 531 | 752 | Active | This one too | 2
5 | 29 | 525 | 753 | Canceled | But this one too | 7
I've read MySQL MIN/MAX all row and also tried this: 我已经阅读了MySQL MIN / MAX所有行并尝试了这个:
SELECT *,MIN(CASE sample.status
WHEN 'Arrived' THEN 1
WHEN 'Active' THEN 2
WHEN 'Pending Approval' THEN 3
WHEN 'Pending Confirmation' THEN 4
WHEN 'Pending Manual' THEN 5
WHEN 'Denied' THEN 6
WHEN 'Canceled' THEN 7
END) AS StatusOrder
FROM sample
WHERE (
(sample.term_id = 29) AND (
StatusOrder = CASE sample.status
WHEN 'Arrived' THEN 1
WHEN 'Active' THEN 2
WHEN 'Pending Approval' THEN 3
WHEN 'Pending Confirmation' THEN 4
WHEN 'Pending Manual' THEN 5
WHEN 'Denied' THEN 6
WHEN 'Canceled' THEN 7
END)
)
GROUP BY bed_id
But this produces an error. 但这会产生错误。 (Also tried replacing StatusOrder with the full CASE statement)
(还尝试用完整的CASE语句替换StatusOrder)
NOTE: I've simplified the actual table which has many more columns. 注意:我已经简化了具有更多列的实际表。 But basically I need access to the whole row that corresponds to the row with the lowest StatusOrder (determined by my case statement) for each bed_id.
但基本上我需要访问每个bed_id对应于具有最低StatusOrder(由我的case语句确定)的行的整行。
Using MySQL 5.5 使用MySQL 5.5
The Below Query works, but it's better to consider replace the column status with status_code
with the code, and have a separate table status(status_code,description)
{denormalise} 下面的查询工作正常,但最好考虑使用
status_code
替换列状态和代码,并具有单独的表status(status_code,description)
{denormalise}
And indexing ( term_id,statUs_code
). 和索引(
term_id,statUs_code
)。
by this, we can just self join. 通过这个,我们可以自己加入。 Instead creating a view like this.
而是创建这样的视图。
SELECT * FROM
(SELECT *,(CASE sample.status
WHEN 'Arrived' THEN 1
WHEN 'Active' THEN 2
WHEN 'Pending Approval' THEN 3
WHEN 'Pending Confirmation' THEN 4
WHEN 'Pending Manual' THEN 5
WHEN 'Denied' THEN 6
WHEN 'Canceled' THEN 7
END) AS status_code FROM SAMPLE
WHERE sample.term_id = 29
) my_view1,
(SELECT BED_ID,MIN(CASE sample.status
WHEN 'Arrived' THEN 1
WHEN 'Active' THEN 2
WHEN 'Pending Approval' THEN 3
WHEN 'Pending Confirmation' THEN 4
WHEN 'Pending Manual' THEN 5
WHEN 'Denied' THEN 6
WHEN 'Canceled' THEN 7
END) AS status_code FROM SAMPLE
WHERE sample.term_id = 29
GROUP BY BED_ID
) my_view2
WHERE my_view1.bed_id = my_view2.bed_id
AND my_view1.status_code = my_view2.status_code
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