[英]Using pointers to input in a struct
I am trying to get some input from the user to a struct in this function: 我试图在此功能中从用户获取一些输入到结构:
void adding(){
Item *x = malloc(sizeof(Item));
printf("Enter an integer.");
scanf("%d", (x->any));
printf("Enter a string.");
scanf("%s", (x->text));
printf("Which set would you like to add the Item to A/B?");
while((scanf("%c", inp)) != ("A"||"B")){
printf("Set does not exist\n");
}
if(A == inp)
add(A, *x);
else
add(B, *x);
}
The Item struct is as follows: Item结构如下:
typedef struct anything{
char text[MAXI];
int any;
}Item;
The add function which is being called in the end is this one: 最后被调用的add函数就是这个:
void add(Array *S,Item *x){
bool rep = false;
int i = 0;
for(i = 0; i<(S->size); i++){
if(compStructs(x,S->arr+i))
rep = true;
}
if(rep == false){
Item *p2 = realloc(S->arr, (S->size+1)*sizeof(Item));
*p2 = *x;
(S->size)++;
}
else
printf("The item is already in the set.");
}
Since a runtime error is occuring when the first scanf() is encountered, I think that I'm doing something wrong in the way I'm handling pointers. 由于遇到第一个scanf()时发生运行时错误,因此我认为我在处理指针的方式上做错了。
Compile with all warnings and debugging info (eg gcc -Wall -g
). 编译所有警告和调试信息(例如
gcc -Wall -g
)。 Learn to use a debugger (eg gdb
). 学习使用调试器(例如
gdb
)。
Then, you should use the result of scanf(3) . 然后,您应该使用scanf(3)的结果。 It gives the number of really read items.
它给出了真正阅读项目的数量。
And while((scanf("%c", inp)) != ("A"||"B"))
is very wrong. 而
while((scanf("%c", inp)) != ("A"||"B"))
是非常错误的。 I'm sure the compiler would have warned you! 我确定编译器会警告您!
Should be 应该
char inp = 0;
while (((inp=0),scanf(" %c", inp) == 1) && inp != 'A' && inp != 'B')
first scanf should give a runtime error. 首先scanf应该给出运行时错误。 scanf expects a location of a variable in which the value read from user would be put.
scanf期望一个变量的位置,将从用户读取的值放在该变量中。
instead of scanf("%d", (x->any));
而不是
scanf("%d", (x->any));
you are supposed to write scanf("%d", &(x->any));
您应该写
scanf("%d", &(x->any));
because when you allocate memory via malloc all the bytes would be assigned value = 0. 因为当您通过malloc分配内存时,所有字节都将被赋值为0。
so basically by writing scanf("%d", (x->any));
所以基本上是通过写
scanf("%d", (x->any));
you are saying put value read from user to memory location 0. which is error. 您是说从用户读取到存储位置0的put值。这是错误的。
there is one more error which i have found in your code is when you are calling add() function. 当您调用add()函数时,我在您的代码中发现了另一个错误。
it expects Item *
as a second argument. 它希望将
Item *
作为第二个参数。 while when you are calling it by add(A, *x);
而当您通过
add(A, *x);
调用它时add(A, *x);
and add(B, *x);
并
add(B, *x);
you are passing Item
and not Item *
. 您传递的是
Item
而不是Item *
。 bcz x itself is a Item *
type variable. bcz x本身是
Item *
类型变量。 so you are supposed to call it like this add(A, x);
所以应该这样称呼它
add(A, x);
. 。
Cheers:) 干杯:)
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