正则表达式捕获一个单词以外的所有内容（一个单词而不是一个字符）

Question

Inputs

a = "Miami, FL"
b = "Boston, MA or Miami, FL"
c = "United Kingdom"

RegEx

loc = re.compile('([^or]+)[,]*[\s]*([A-Z]+)')
locs = loc.findall(b)

How can I make it break at or ? It will break at o I know. And [^(or)] and [^\\(or\\)] won't work either.

Answer 1

It seems like you want split string by or . Use re.split :

>>> b = "Boston, MA or Miami, FL"
>>> re.split(r'\bor\b', b)
['Boston, MA ', ' Miami, FL']

---

>>> re.findall(r'(?:^|or)\s*([^,]+,?\s[a-z]+)', a, flags=re.I)
['Miami, FL']
>>> re.findall(r'(?:^|or)\s*([^,]+,?\s[a-z]+)', b, flags=re.I)
['Boston, MA', 'Miami, FL']
>>> re.findall(r'(?:^|or)\s*([^,]+,?\s[a-z]+)', c, flags=re.I)
['United Kingdom']

Answer 2

这应该为您工作：

loc = re.compile('(?:^|or)\s*([^,]+),\s([A-Z]+)')