如何从目录中的所有xml文件获取特定属性？

Question

I have a folder full of xml files. In these files many of them share a common attribute (Name), but have a secondary attribute that is different. I want to get a list of the unique entries based off reading these xml files. Below is an example of what the various xml files will contain.

File 1

<?xml version="1.0" encoding="UTF-8"?>
<results date="2013-12-29">
<A uniqueId="1234" Name="My-Machine"/>
<error number="555">
<description><![CDATA[House on Fire]]></description>
</error>
</results>

File 2

<?xml version="1.0" encoding="UTF-8"?>
<results date="2013-12-29">
<A uniqueId="1234" Name="My-Machine"/>
<error number="556">
<description><![CDATA[House in flood]]></description>
</error>
</results>

File 3

<?xml version="1.0" encoding="UTF-8"?>
<results date="2013-12-29">
<A uniqueId="1234" Name="My-Machine"/>
<error number="556">
<description><![CDATA[House in flood]]></description>
</error>
</results>

I need to be able to read all the files, add each Name and description to a list (or possibly array). Output from example would look like this:

Name="MyMachine", description="![CDATA[House is flooding]]";    
Name="MyMachine", description="![CDATA[House on fire]]";    
Name="MyMachine", description="![CDATA[House on fire]]";

It seems LINQ may be the best way to handle this since the files are very small in content.

Answer 1

Here is a way to read that description element content from one file:

var xDoc = XDocument.Load("Input.xml");
var name = "My-Machine";

var aElement = xDoc.Root.Element("A");

string description = null;
if ((string)aElement.Attribute("Name") == name)
    description = (string)xDoc.Root.Element("error").Element("description");

It will return the element value when Name attribute value matches your name variable. Otherwise description will be null .