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如何从数组列表创建数组

[英]How to create an array from an arraylist

ArrayList<Student> alist = new ArrayList();
// object type is student
//arraylist contains student objects        
Student[] arr= new Student[un.size()];

for(int i = 0; i <= alist .size(); i++){
    them[i] = arr.get(i);
}

What I want to do is to create an array of students without getting the array out of bounds exception. 我想做的是创建一个学生数组,而不会使数组超出范围。

Arrays are zero-based in Java (and most languages). 数组在Java(和大多数语言)中从零开始 If you have an array of size N , the indexes will be from [0, N-1] (Total size of N ). 如果你有大小的数组N ,索引将是从[0,N-1](总的大小N )。

i <= alist .size() 

should be 应该

i < alist .size()
   ↑
 No "=" 

Why don't you simply use toArray ? 为什么不简单地使用toArray

You are very close. 你很亲密 Your for loop condition says to loop as long as i is less than or equal to alist.size() . 您的for循环条件表示只要i小于或等于alist.size()就会alist.size() If you do that, you'll always run one over. 如果这样做,您总是会一遍又一遍。

For example, if you only have one item in alist , your size will be 1, but you really only want to loop until 0. 例如,如果alist只有一项,则大小将为1,但实际上您只想循环到0。

Change this: 更改此:

for(int i = 0; i <= alist.size()  ; i++)

To this: 对此:

for(int i = 0; i <  alist.size()  ; i++)

All you really need is to say is them = alist.toArray(new Student[them.length]) . 您真正需要说的是them = alist.toArray(new Student[them.length]) This will simply copy the data over. 这将简单地复制数据。

ArrayList<Student> alist = new ArrayList();
// object type is student
//arraylist contains student objects        
Student[] arr= new Student[un.size()];
alist.toArray(arr);

You can try like this also, All above ans are correct but this is simple and easy 您也可以这样尝试,以上所有答案都是正确的,但这很简单

String[] arr = alist.toArray(new Student[un.size()]);

list.toArray return an array containing all of the elements in this collection list.toArray return an array containing all of the elements in this collection

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