[英]Why does this Java code throw an exception?
I am new with java.我是java新手。 I having some exception while running my code:
我在运行我的代码时遇到了一些异常:
import java.util.Random;
public class Example {
public static void main(String[] args) {
Random r = new Random();
int[] num= new int[5];
for (int i= 0; 1<num.length; i++)
{
num[i]= r.nextInt(100)+1;
System.out.println(num[i]);
}
}
}
It gives me the following exception:它给了我以下异常:
Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 5 at Example.main(Example.java:13)
线程“main”中的异常 java.lang.ArrayIndexOutOfBoundsException: 5 at Example.main(Example.java:13)
Why am I getting this exception?为什么我会收到此异常?
Firstly, you should always copy and paste the exception text, to save us trying to guess which type of exception it is or where it's happening首先,您应该始终复制并粘贴异常文本,以免我们尝试猜测它是哪种类型的异常或它发生的位置
You'll be getting an ArrayOutOfBoundsIndexException
, because the loop is endless yet the index always increments.你会得到一个
ArrayOutOfBoundsIndexException
,因为循环是无止境的,但索引总是增加。
for (int i= 0; 1<num.length; i++)
One is always less than the length
of num
so it loops for ever, incrementing i
each time until i
is larger than the array size.一个总是小于
num
的length
,因此它永远循环,每次递增i
直到i
大于数组大小。 At which point you'll try to do this此时你会尝试这样做
num[i] ...
And i
will be out of bounds, throwing the exception. i
会越界,抛出异常。
import java.util.Random;
public class test {
public static void main(String[] args) {
Random r = new Random();
int[] num = new int[5];
for (int i = 0; i < num.length; i++) {
num[i] = r.nextInt(100) + 1;
System.out.println(num[i]);
}
}
}
This is how a loop works:这是循环的工作方式:
for (initialization; termination; increment) {
statement(s)
}
When the termination expression evaluates to false, the loop terminates.当终止表达式的计算结果为假时,循环终止。 In your case the loop never terminates.
在您的情况下,循环永远不会终止。 That is why you are getting an
ArrayOutOfBoundsIndexException
.这就是您收到
ArrayOutOfBoundsIndexException
。
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