根据另一个表的最小值选择表的属性

Question

My table structure is

I want to get the recent video uploaded of the user

What I want to do is:

"select video_id of a record who is having minimum of timestamp where userid='something'"

What I currently have is:

$recent_video = "$db->query("
  SELECT video_id 
  FROM video_primary 
  ORDER BY timestamp DESC LIMIT 1 
  WHERE userid = '$userid'"
) or die($db->error);"`


while($row=mysqli_fetch_assoc($recent_video))
{
  $video_id=$row['video_id'];
}
echo $video_id;

My table data is

How do I get the most recent view uploaded by the user?

Answer 1

Write WHERE clause after FROM part

Try this:

SELECT vp.video_id 
FROM video_primary vp
WHERE userid='$userid'
ORDER BY vp.timestamp DESC 
LIMIT 1;

Answer 2

try this

$recent_video=$db->query("select video_id from video_primary where userid='$userid' 
    ORDER BY timestamp DESC LIMIT 1 ") or die($db->error);

instead of

$recent_video="$db->query("select video_id from video_primary ORDER BY timestamp DESC
    LIMIT 1 where userid='$userid'") or die($db->error);"

you are using where clause after order by and limit 1 which is a syntax error. see tutorial

Tutorial

Answer 3

There is a specific sequence of every clause in Query statement. Below is the sequence:

• Select
• Where
• Order by
• Limit

So, as per the above sequence, you should correct your query like below. Also, you should place double quote(") correctly.

$recent_video = $db->query(" SELECT video_id FROM video_primary WHERE userid = '$userid' ORDER BY timestamp DESC LIMIT 1" ) or die($db->error);