Python for循环计数器列表-计数器不起作用

Question

Could someone please help me troubleshoot my code. I have two lists.

    A = [['2925750', ' Everything he mentioned, I could have evaluated on my own'], ['2925750', ' I do wish he could have shown us more at this point that could have set the fox apart.']]

B = ['mentioned','evaluated','fox','wish']

The goal is to append to list A the number of times any item in B is present in a sentence for A.

The result should be something like:

[(['2925750', ' Everything he mentioned, I could have evaluated on my own'], 0), (['2925750', ' I do wish he could have shown us more at this point that could have set the Equinox apart.'], 0)]

The problem is my count is zero.

Below is my code. Thank you in advance:

Y = []


##Find Matches
for sent in A:
  for sent in B:
      Y.append((sent, sum(sent.count(col) for col in B)))

Thank you.

Answer 1

The variable sent in for sent in B overshadows the variable in for sent in A . Or, to be more exact, it assigns to the same name (same variable).

You should rename one of them.

Also, note you already iterate over B inside sum . In the inner loop, you probably meant to iterate over each of the lists in A .

for lst in A:
  for sent in lst:
      Y.append((sent, sum(sent.count(col) for col in B)))

Answer 2

您不能将sent用作两个循环的迭代器，因为它仍在范围内。

Answer 3

• you used 'sent' twice.

• You don't need a loop for B.

• 'A' is a list of lists.

My fix:

Y = []
A = [['2925750', ' Everything he mentioned, I could have evaluated on my own'], ['2925750', ' I do wish he could have shown us more at this point that could have set the fox apart.']]
B = ['mentioned','evaluated','fox','wish']

for sent in A:
    o = 0
    for i in sent:
        o +=sum(i.count(col) for col in B)
    Y.append((sent, o))

Y:

[(['2925750', ' Everything he mentioned, I could have evaluated on my own'], 2), (['2925750', ' I do wish he could have shown us more at this point that could have set the fox apart.'], 2)]