如何以列表或元组的形式输入参数？

Question

Is it possible to enter the parameters of function in form of a list. For example -

list1 = ["somethin","some"]
def paths(list):
    import os
    path = os.path.join() #I want to enter the parameters of this function from the list1
    return path

Okay i got my answer but just an aditional question, related to this only - here is my code -

def files_check(file_name,sub_directories):
    """
        file_name :The file to check
        sub_directories :If the file is under any other sub directory other than the   application , this is a list.
    """
    appname = session.appname
    if sub_directories:
        path = os.path.join("applications",
                        appname,
                        *sub_directories,
                         file_name)
        return os.path.isfile(path)
    else:
         path = os.path.join("applications",
                        appname,
                        file_name)
         return os.path.isfile(path)

i am getting this error -

 SyntaxError: only named arguments may follow *expression

Please help me .

Answer 1

You can unpack the sequence using the splat operator( * ):

path = os.path.join(*my_list)

Demo:

>>> import os
>>> lis = ['foo', 'bar']
>>> os.path.join(*lis)
'foo\\bar'

Update:

To answer your new question you cannot pass positional arguments once you've used * in arguments, you can do something like this here:

from itertools import chain

def func(*args):
    print args

func(1, 2, *chain(range(5), [2]))
#(1, 2, 0, 1, 2, 3, 4, 2)

And don't use list as a variable name

Answer 2

只需使用*运算符解压缩列表

path = os.path.join(*list) 

Answer 3

You can use the *-operator to unpack the arguments .

For Example

data = ['a','b'] os.path.join(*data)

Gives

'a/b'