[英]How do I convert this pseudo-code and what list do I need for the formula
I've been given a computing assignment to create randomly generate game levels using pseudo-code and algorithms. 我已经获得了一个计算任务,可以使用伪代码和算法创建随机生成的游戏关卡。 The map must be printed using #'s and spaces and cells with fewer than 3 neighbors die.
必须使用#来打印地图,空格和少于3个邻居的像元将死亡。 But we have been told to work it out without covering either and it's safe to say I have no idea what I'm doing.
但是我们被告知要解决这个问题而不涉及任何一个,可以肯定地说我不知道自己在做什么。 Any help would be appreciated...
任何帮助,将不胜感激...
Here's the whole code: 这是整个代码:
# -*- coding: utf-8 -*-
import random
def create_random_map(height, width):
map = []
for y in range(height):
for x in range(width):
map.append( bool(random.randint(0,1)) )
return map
def apply_cellular_automaton(map, height, width, born, survive):
return map
def draw_map(map, height, width):
pass
height = 45
width = 79
map = create_random_map(height, width)
for i in range(5):
map = apply_cellular_automaton(map, height, width, [6, 7, 8], [3, 4, 5, 6, 7, 8])
for i in range(3):
map = apply_cellular_automaton(map, height, width, [5, 6, 7, 8], [5, 6, 7, 8])
draw_map(map, height, width)
Pseudo-code I have been given 我得到的伪代码
PROCEDURE draw_map(map, height, width)
FOR EACH grid row
CREATE AN EMPTY row
FOR EACH cell in row
IF cell IS alive
ADD ‘#’ TO row
ELSE
ADD ‘ ‘ TO row
PRINT row
Formula example I have been given 我得到的公式示例
i = (y * width) + x
61 = (7 * 8) + 5
You might first work out a viable structure for map. 您可能首先会设计出可行的地图结构。 map needs to be a two dimensional structure.
地图必须是二维结构。 One way of doing that is to make map a list-of-lists ie a list of rows where each rows elements are column of that row.
一种实现方法是使map成为列表列表,即行列表,其中每个行元素都是该行的列。 See Create a two-dimensional array at runtime on the Rosetta Code site.
请参阅Rosetta Code网站上的在运行时创建二维数组 。
Next populate an array and try and turn your draw_map pseudo-code into proper Python around your implementation of a 2D array. 接下来,填充一个数组,然后尝试将您的draw_map伪代码转换为围绕2D数组实现的适当Python。
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