[英]I'm trying to pull data from database into selectboxes
I'm trying to pull data from database into selectboxes, but when the data is pulled it goes into one 'td' and not into separate td's. 我正在尝试将数据从数据库中提取到选择框中,但是当数据被拉出时,它会进入一个'td',而不是进入单独的td。 I'm trying to achieve result as shown below
我正在努力实现如下所示的结果
but I keep getting this result 但我一直得到这个结果
here is my code 这是我的代码
<?php
$data_array = array();
$result2 = mysql_query("SELECT * FROM `firefightersonscene`
JOIN `firefighterinfo` ON `firefightersonscene`.`FireFighterInfo_fighterID` = `firefighterinfo`.`fighterID`
JOIN `stationlocation` ON `firefighterinfo`.`StationLocation_locationID`=`stationlocation`.`locationID`
WHERE `IncidenceOfFire_incidentID`='$getIncID' ORDER BY `firstName`");
if(mysql_num_rows($result2) > 0)
{
while($rows2 = mysql_fetch_object($result2))
{
$data_array[] = $rows2;
}
}
?>
<form action="core_viewfireoccurrence.php?incidentID=<?php echo $rows->incidentID; ?>" method="post" class="view_occurrence_form">
<table id="myTable">
<thead>
<tr>
</tr>
</thead>
<tbody>
<tr>
<td class="count">1</td>
<td>
<?php
foreach($data_array as $rows2):
$fighterID = $rows2->FireFighterInfo_fighterID;
$results = mysql_query("SELECT `fighterID`, `firstName`, `middleName`, `lastName`, `stationlocation`.`exactlocation`
FROM `firefighterinfo`
JOIN `stationlocation` ON `firefighterinfo`.`StationLocation_locationID`=`stationlocation`.`locationID` ORDER BY `firstName`");
echo '<select name="fireman[]" required><option value=""></option>';
while($row = mysql_fetch_array($results))
{
if($row['fighterID'] == $fighterID)
echo '<option selected>'. $row['firstName']." ".$row['middleName']." ".$row['lastName'].", ".$row['exactlocation'].'</option>';
else
echo '<option>'. $row['firstName']." ".$row['middleName']." ".$row['lastName'].", ".$row['exactlocation'].'</option>';
}// end while
echo '</select><br>';
endforeach;
?>
</td>
<td>
<input type="button" value="X" class="removeVar"/>
</td>
</tr>
</tbody>
<tfoot>
<tr>
<td>
<input type="button" id="addVar" value="Add Item"/>
</tr>
</tfoot>
</table>
</form>
JS CODE JS代码
<script type="text/javascript">
$('form').on('click', '.removeVar', function(){
$(this).closest('tr').remove();
$('.count').each(function(i){
$(this).text(i + 1);
});
});
//add a new node
$('#addVar').on('click', function(){
var varCount = $('#myTable tr').length - 1;
$node = ['<tr>',
'<td class="count">'+varCount+'</td>',
'<td><select name="fireman[]" class="ctlGroup" required>',
'<option value=""></option>',
'<?php require("php/fireman_list.php"); ?>',
'</select></td>',
'<td><input type="button" value="X" class="removeVar"/>',
'</td></tr>'].join('\n');
$('#myTable > tbody:last').append($node);
});
</script>
You need to put your whole table row in the loop. 您需要将整个表行放在循环中。 You will also need to add a variable to count the row number for you.
您还需要添加一个变量来为您计算行号。
<?php
$row =1;
foreach($data_array as $rows2):
?>
<tr>
<td class="count"><?php echo $row; ?></td>
<td>
<?php
$fighterID = $rows2->FireFighterInfo_fighterID;
$results = mysql_query("SELECT `fighterID`, `firstName`, `middleName`, `lastName`, `stationlocation`.`exactlocation`
FROM `firefighterinfo`
JOIN `stationlocation` ON `firefighterinfo`.`StationLocation_locationID`=`stationlocation`.`locationID` ORDER BY `firstName`");
echo '<select name="fireman[]" required><option value=""></option>';
while($row = mysql_fetch_array($results))
{
if($row['fighterID'] == $fighterID)
echo '<option selected>'. $row['firstName']." ".$row['middleName']." ".$row['lastName'].", ".$row['exactlocation'].'</option>';
else
echo '<option>'. $row['firstName']." ".$row['middleName']." ".$row['lastName'].", ".$row['exactlocation'].'</option>';
}// end while
echo '</select><br>';
?>
</td>
<td>
<input type="button" value="X" class="removeVar"/>
</td>
</tr>
<?php
$row++;
endforeach;
?>
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