jQuery数组到表“ TD”

Question

I have an array (created dynamically) that would look like [one,two,three,four,five,six]

I have a table (created dynamically) with the same number of rows as items in the array

<table>
   <tr>
     <td><td>
     <td>content</td>
   </tr>
   <tr>
     <td><td>
     <td>content</td>
   </tr>
   <tr>
     <td><td>
     <td>content</td>
   </tr>
   <tr>
     <td><td>
     <td>content</td>
   </tr>
   <tr>
     <td><td>
     <td>content</td>
   </tr>
   <tr>
     <td><td>
     <td>content</td>
   </tr>
</table>

My goal, is to place the array item in the td:first-of-type in the row with the corresponding index() value as array position.

I generally dont ask question this early on, but I'm clueless on how to go about doing this. This one is a little over my head?

Answer 1

each gives everything to you almost out-of-the-box:

$("tr").each(function(index, elem){
    $(this).find("td").first().text(yourArray[index]);
})

Answer 2

Ok, maybe loop through them like this:

$("table tr").each(function(index) {
      $(this).children("td").first().html(myArray[index]);
});