在回显的字符串中使用变量，如何“结束”变量？

Question

where $q is q

echo "asd$q";

will output asdq

echo "asd$q_";

will look for $q_ and since thats null, it will print asd

to get "asdq_" what should I do ?

Answer 1

You can concatenate the variable with the string using .

$q='q';
echo 'asd'.$q.'_';

Answer 2

Do like this.. Enclose the $q variable under curly braces.

<?php
$q='q';
echo "asd{$q}_"; //"prints" asdq_