[英]What is wrong in my SQL query?
I have a query that joins two table, and it keeps getting the error. 我有一个连接两个表的查询,并且不断收到错误。
You have an error in your SQL syntax;
您的SQL语法有误; check the manual that corresponds to your MySQL server version for the right syntax to use near '0' at line 1`.
查看与您的MySQL服务器版本相对应的手册以获取正确的语法,以在第1行的“ 0”附近使用。
I can't seem to figure out what is wrong here? 我似乎无法弄清楚这里出了什么问题?
I've already check this but in my case it is different. 我已经查这个 ,但我的情况是不同的。
Here is my query: 这是我的查询:
$sQuery = "SELECT SQL_CALC_FOUND_ROWS A.id, A.studentNum, B.lastName, B.firstName, B.middleName, B.year, B.courseBlock, B.status, A.facultyloading_id"+
" FROM table_enrolledstudents AS A"+
" INNER JOIN table_student AS B"+
" ON A.studentNum = B.studentNum";
What do you think is wrong? 你觉得错什么? Can you help me?
你能帮助我吗? Thank you!
谢谢!
Use the PHP string concatenation operator .
使用PHP字符串连接运算符
.
(dot). (点)。
Or to improve readability/maintainability you could also put the query into a single string with line breaks. 为了提高可读性/可维护性,您还可以将查询放入带有换行符的单个字符串中。
$sql = "SELECT SQL_CALC_FOUND_ROWS A.id, A.studentNum, B.lastName, B.firstName, B.middleName, B.year, B.courseBlock, B.status, A.facultyloading_id
FROM table_enrolledstudents AS A
INNER JOIN table_student AS B
ON A.studentNum = B.studentNum";
Explanation: This is because PHPs type system allows arithmetic operations on strings (which can contain numbers), eg "1" + "2"
would return the sum, which is 3
. 说明:这是因为PHPs类型系统允许对字符串(可以包含数字)进行算术运算,例如
"1" + "2"
将返回总和,即3
。 If a string used in an arithmetic operation does not contain a parsable number, then it is treated as zero, so the result of "abc" + 5
is 5
. 如果在算术运算中使用的字符串不包含可分析的数字,则将其视为零,因此
"abc" + 5
的结果为5
。
As Mr. Aleksander Bavdaz said, I have replaced the plus and make it a dot and the error is gone. 正如亚历山大·巴夫达兹(Aleksander Bavdaz)先生所说,我已将加号替换成一个点,并且错误消失了。 Here is my new query.
这是我的新查询。 Thank you for your help!
谢谢您的帮助!
$sQuery = "SELECT SQL_CALC_FOUND_ROWS A.id, A.studentNum, B.lastName, B.firstName, B.middleName, B.year, B.courseBlock, B.status, A.facultyloading_id".
" FROM table_enrolledstudents AS A".
" INNER JOIN table_student AS B".
" ON A.studentNum = B.studentNum"
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