如何让CodeIgniter忽略输入到URL中的最后一个段 - 但仍保留在那里？

Question

I'm using CodeIgniter to build a user profile section from scratch. What happens is, the user will put in the URL:

www.somesite.com/profile/view/<USERNAME>

( profile is the folder & view is the controller)

and I will use IF ELSE statements to check to see if $currentURL (see below) is in the DB and load the required page.

But what's happening right now is it's looking for a function(I think) inside view to execute. But there is none. Which results in a 404 error.

Is it possible for CodeIgniter to ignore the last segment of that URL but still keep it there so that I can use;

$currentURL = $this->uri->segment(3);

to grab the USERNAME ?

Thanks for viewing my question,

Lewis.

Answer 1

If I understand you correctly:

declare your function as follows

\n

public function view($var1, $username = "") {...}

where $var1 must be filled in but $username can be ommited and its default value is ""

---

<?php if ( ! defined('BASEPATH')) exit('No direct script access allowed');

class View extends CI_Controller { //can not belive that View is not reserved word

    public function __construct() {
        parent::__construct();
    }

    public function index() {
        //index() function can not have parameters
        //redirect('view/show');
        //if no username is set, do default thing like show list of users
        //load view or something
    }

    public function show($username = "") {
        //this function can have parameters
        //load views from here
        $this->load->view('abc_view');
    }
}

Add to routes.php following

$route['profile/view/(:any)'] = "profile/view/show/$1";

this will allow you to have nice URL as you expect

site.com/profile/view/Peterson123

NOTE when using "routing" method do not redirect(profile/view/show) in index()

---

Another aproach that uses _remap() is explained here .