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在字符串中逐字逆序

[英]Reverse word by word in a String

I am trying to reverse the words in a string word by word. 我正在尝试逐字反转字符串中的单词。 But I am running into a bit of trouble. 但是我遇到了麻烦。 I know many people have used StringBuilder to do this problem but I wanted to try it out without it. 我知道很多人都使用StringBuilder来解决这个问题,但是我想在没有它的情况下进行尝试。

Input: 输入:

Hi there

Output: 输出:

iH ereht

Currently, my input string stops at the last word. 目前,我的输入字符串停在最后一个单词。 I assume this is due to the fact that in my code, the reverse portion of the code only reverses when a ' ' or space is detected. 我认为这是由于以下事实:在我的代码中,代码的反向部分仅在检测到' '或空格时才反向。 I changed this by performing the reverse portion when the end of the string has been reached as well. 我也通过在到达字符串末尾时执行反向部分来更改此设置。 ( i == len ) However this does not seem to fix the problem. i == len )但是,这似乎无法解决问题。 I assume there is some logic error inside my if , else if statements and for loop as well. 我假设ifelse if语句和for loop中也存在一些逻辑错误。 I was wondering if anyone could guide me in the right direction. 我想知道是否有人可以引导我朝正确的方向前进。

The test case string that I've been working on is 我一直在努力的测试用例字符串是

"Hi there Mr.Doge!"

The output I get right now is 我现在得到的输出是

iH ereht <-- space at the end of the string. iH ereht <-字符串末尾的空格。

I printed some text as the code proceeds and the last word ( Mr.Doge! ) is being stored into temp but it is not being reverse. 随着代码的进行,我打印了一些文本,最后一个单词( Mr.Doge! )被存储到temp但没有反向。

Here is the output when I compile the code: 这是我编译代码时的输出:

0
H
1
Hi
2
i
iH
3
t
4
th
5
the
6
ther
7
there
8
iH e
iH er
iH ere
iH ereh
iH ereht
9
M
10
Mr
11
Mr.
12
Mr.D
13
Mr.Do
14
Mr.Dog
15
Mr.Doge
16
Mr.Doge!
iH ereht 

My code: 我的代码:

public static String reverseWord(String str){
    int len = str.length();
    String reverse = "", temp = "";

    for (int i = 0; i < len; i++) {
        System.out.println(i);
        if (str.charAt(i) != ' '){
            temp += str.charAt(i);
            System.out.println(temp);
        }
        else if (str.charAt(i) == ' ' || i == len){
        //if (str.charAt(i) == ' ') {
            for (int j = temp.length() - 1; j >= 0; j--) {      // reverse
                reverse += temp.charAt(j);                      // append in reverse
                System.out.println(reverse);
            }
            reverse += ' ';
            temp = "";
        }
    }
    return reverse;
}

With a couple of modifications this must work. 经过几处修改,该方法必须有效。 See comments in code, to see what I modified. 查看代码中的注释,以查看我所做的修改。

Code: 码:

public static void main(String[] args)
{
    System.out.println(reverseWord("Hello world Liondancer"));
}

public static String reverseWord(String str)
{
    int len = str.length();
    String reverse = "", temp = "";

    for (int i = 0; i < len; i++) {   // i == len comparison is unuseful since 'i' won't never be 'len'
        if (str.charAt(i) != ' ') {
            temp = str.charAt(i) + temp; // What you did, but add the current character first, THIS IS THE REVERSE!!!
        } else if (str.charAt(i) == ' ') {
            reverse += temp + " ";
            temp = "";
        }
    }
    reverse += temp; // Added this outside the loop to add last word stored in 'temp'
    return reverse;
}

Output: 输出:

olleH dlrow recnadnoiL

Note: 注意:

I deleted the nested for since it is not necessary. 我删除了嵌套for ,因为它是没有必要的。

try this change 试试这个变化

    for (char c : str.toCharArray()) {
        if (c != ' '){
            temp = c + temp;
        } else {
            reverse += temp + ' ';
            temp = "";
        }
    }
    reverse += temp;

Reverse outside your loop and check that you're not at the last word (like so) - 在循环外倒转,并检查自己是否不是最后一个单词(像这样)-

public static String reverseWord(String str) {
  int len = str.length();
  String reverse = "", temp = " ";

  for (int i = 0; i < len; i++) {
    if (str.charAt(i) != ' ') {
      temp += str.charAt(i);
    } else if (str.charAt(i) == ' ' || i == len) {
      if (i + 1 < len) {
        for (int j = temp.length() - 1; j >= 0; j--) { // reverse
          reverse += temp.charAt(j); // append in reverse
        }
        temp = " ";
      } else {
        temp = "";
      }
    }
  }
  for (int j = temp.length() - 1; j >= 0; j--) { // reverse
    reverse += temp.charAt(j); // append in reverse
  }
  return reverse;
}

If i were to do it I would just store entire string in an arraylist. 如果我要这样做,我只会将整个字符串存储在arraylist中。 then say: 然后说:

for(i=0;i<len;i++)
    temp.size()=len;
    temp(length-i)=str(i);
    print temp;

You can use the loop in this way too... 您也可以通过这种方式使用循环...

   public String reverseString(String str){
       String reverse="";

       for(int i=str.length()-1; i>=0; i--){

           reverse = reverse + str.charAt(i);

       }
          return reverse;

   }

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