PHP array_walk require_once

Question

I was just wondering if anyone knew why I can't use require_once as a callback for array_walk . I can just include it in an anonymous function and run that, but it gives an invalid callback error for the usage:

$includes = array(
    'file1.php',
    'file2.php',
    'file3.php'
);
array_walk($includes, 'require_once');

Answer 1

require_once不是PHP函数，而是控制结构。

Answer 2

You could create

function my_require_once ($name)
{
    require_once $name;
}

The other guys are right, it's not a function. It operates outside the mode of the PHP code you write. The contents of the file are brought into the global namespace, even if it is called within a functiion, as above.

I use this, for example to do stuff like

function my_log ($message, $extra_data = null)
{
    global $php_library;
    require_once "$php_library/log.php"; // big and complicated functions, so defer loading

    my_log_fancy_stuff ($message, $extra_data);
}

Answer 3

You are going to waste more time finding out what's wrong. Just use:

$includes = array(
    'file1.php',
    'file2.php',
    'file3.php'
);
foreach($includes as $include) {
    require_once($include);
}

Answer 4

As Martin wrote, require once is not a function, so your solution with array_walk is not been working. If you want to include multiple files, you can try to use this:

function require_multi($files) 
{
    $files = func_get_args();
    foreach($files as $file)
    {
        require_once($file);
    }
}

Usage:

require_multi("fil1.php", "file2.php", "file3.php");