mysql查询中的价格比较

Question

I have a price:

$price = 100;

I have 2 Database fields

1) priceType
2) price

Now the cases are:

if priceType =1

CASE 1: price <= $price // Do this comparison in WHere Clause

if priceType =2

CASE 2: price* (800000 / 1000) <= '$price' // Do this comparison in WHere Clause

Only one operation should be performed at a time, depends on priceType.

If priceType = 1 than the $price should be compared in first case way.

If priceType = 2 than the $price should be compared in second case way.

I want to perform this in Where Clause.

What should the query look like ?

Answer 1

Try this:

SELECT * FROM tableA
WHERE (CASE priceType WHEN 1 THEN price WHEN 2 THEN price * (800000 / 1000) END) <= $price

Answer 2

or with IF :

SELECT
    IF (priceType = 1, price,
        IF (priceType = 2, price * (800000 / 1000),
            'unknown priceType'
        )
    ) AS price
FROM priceTable

Update:

I maybe missunderstood...

SELECT price
FROM priceTable
WHERE (priceType = 1 AND price <= " . $price . ")
OR    (priceType = 2 AND (price* (800000 / 1000)) <= " . $price . ")