[英]Creating a very simple jQuery plugin, not working
I've never created a jQuery plug-in before. 我以前从未创建过jQuery插件。 I'm trying it out and keeping it simple for now- here's my plug-in code which is hosted on a CDN in my company:
我现在正在尝试并保持简单 - 这是我的插件代码,它在我公司的CDN上托管:
(function ($) {
$.fn.displayToastrNotifications = function () {
alert('test');
};
})(jQuery);
I'm referencing this JavaScript file inside my page: 我在我的页面中引用了这个JavaScript文件:
<script src="http://server/sites/CDN/Scripts/toastr-notifications.js"></script>
Finally, in the same page, I have: 最后,在同一页面中,我有:
$(document).ready(function () {
$.displayToastrNotifications();
});
Am I doing this right? 我这样做了吗? The JavaScript file containing my plug-in code is being brought back to the browser per Firebug.
包含我的插件代码的JavaScript文件将根据Firebug返回到浏览器。 I do not get an alert box when I refresh my page.
刷新页面时,我没有收到警告框。 What am I doing wrong?
我究竟做错了什么?
EDIT 编辑
The console reports an error: 控制台报告错误:
TypeError: $.displayToastrNotifications is not a function
TypeError:$ .displayToastrNotifications不是函数
$.displayToastrNotifications();
$ .displayToastrNotifications();
But, it is a function, at least I think it is... 但是,这是一个功能,至少我认为它是......
No, that's not right. 不,那不对。 You're adding the function to
$.fn
, so that means it's something to be used as a method of jQuery objects: 您将函数添加到
$.fn
,这意味着它可以用作jQuery对象的方法:
$(something).displayToastrNotifications();
If you want a "global" function like $.ajax
, then you'd set it up as just a property of $
, not $.fn
. 如果你想要一个像
$.ajax
这样的“全局”函数,那么你将它设置为$
的属性,而不是$.fn
。
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