通过int值过滤具有NSDictionary的NSArray

Question

I have the following NSArray:

(
        {
        establecimiento = 15;
        internet = 500;
    },
        {
        establecimiento = 0;
        internet = 1024;
    },
        {
        establecimiento = 24;
        internet = 300;
    }
)

And I need to filter the array for establecimiento < 10 .

I'm trying this:

NSPredicate *predicate = [NSPredicate predicateWithFormat:@"establecimiento = %@", [NSNumber numberWithInt:self.establecimientoFiltro]];

where self.establecimientoFiltro is an int with value: 10

But I have as result an empty array.

Hope to be clear with my question and thank you in advance for your answers.

Regards, Victor

Answer 1

Your predicate checks to see if the value is equal to ten, not less than ten. You receive an empty array because that you provided us with does not contain a dictionary where the establecimiento key returns a value of 10.

NSPredicate *predicate = [NSPredicate predicateWithFormat:@"establecimiento < 10"];

Answer 2

You should use blocks with Predicate to achieve this.

Let's assume your array is in myArray . Now make a predicate with range of your choice. As of now, you want it to be less than 10 for establecimientoFiltro .

NSPredicate *keyPred = [NSPredicate predicateWithBlock:^BOOL(id  obj, NSDictionary *bindings) {
    NSRange myRange = NSMakeRange (0, 9);
    NSInteger rangeKey = [[obj valueForKey:@"establecimientoFiltro"]integerValue];
    if (NSLocationInRange(rangeKey, myRange)) {
        // found
        return YES;
    } else {
        // not found
        return NO;
    }
}];

NSArray *filterArray = [myArray filteredArrayUsingPredicate:keyPred];
NSLog(@"%@", filterArray);

You get your result filtered in the filteredArray .

Hope that is the efficient most & helpful to you.