如何在字符串（Java）中剪切关键字？

Question

I have the following string in Java:

String test = "Goof 23N, 45, 88, GOOF 33*, 12-24";

Now i want to cut the word "Goof" away from the String and i want to save the originally 23N input in a separate string (but how can a delete this keyword and save the originally input "23N" or "33*")

for(String tmpTest : test.split(",")){

  if (tmpTest.toLowerCase.contains("goof")){
      String separateString = // implementation unclear
  }

}

Answer 1

May be you can try this out:

    String test = "Goof 23N, 45, 88, GOOF 33*, 12-24";
    String value = test.replaceFirst("Goof", "");

Output: 23N, 45, 88, GOOF 33*, 12-24

Or, if you need to remove all the versions of 'Goof' without case matching then check this :

    String test = "Goof 23N, 45, 88, GOOF 33*, 12-24";
    // (?i) in the below regex will ignore case while matching
    String value = test.replaceAll("(?i)Goof\\s*", "");

Output: 23N, 45, 88, 33*, 12-24

Answer 2

Something like this may help you. Replace your if statement with the one below.

int index = tmpTest.toLowerCase().indexOf("goof");
if (index >= 0) {
  String value = tmpTest.substring(index + 5);
}

Also, be careful with the compile errors you have in your code.

Answer 3

You can use a function replaceAll(String regex, String replacement)

String test = "Goof 23N, 45, 88, GOOF 33*, 12-24";
test = test.replaceAll("Goof","").replaceAll("GOOF","");

Answer 4

You would want to use replaceAll with regex ignoring case . You can use Pattern.quote() for this purpose:

String keyword = "gOOf";

String test = "Goof 23N, 45, 88, GOOF 33*, 12-24";
String replaceString = "(?i)" + Pattern.quote(keyword);

test = test.replaceAll(replaceString, "");
System.out.println(test);

Output:

23N, 45, 88, 33*, 12-24

Here, it doesn't matter how 'gOOf' is written it would replaceAll occurrences using the regex.

Answer 5

Just one more way to do it...

        String text = "Goof     23N, 45, 88, GoOF 33*, 12-24";
        //if you want to remove trailing spaces use 'goof\\s*' as regex
        String regex="goof";
        Pattern p = Pattern.compile(regex, Pattern.CASE_INSENSITIVE);  
        Matcher m = p.matcher(text);        
        System.out.println(m.replaceAll(""));

Answer 6

final String GOOF = "goof";
String input = "Goof 23N, 45, 88, GOOF 33*, 12-24";
String inputLawerCase = input.toLowerCase();
String inputWithoutGoof = inputLawerCase.replaceFirst(GOOF, "");
String output = input.substring(input.length() - inputWithoutGoof.length());

//In case Goof is not at the beginning of the string
int goofIndex = inputLawerCase.indexOf(GOOF);
output = input.substring(0, goofIndex) + input.substring(goofIndex + GOOF.length());

Answer 7

Time for a little pseudocode me thinks.

You want to split the String up into tokens . You can do this using String.split() .

Let input equal "this, is, just, a, GOOFtest".
// It's a comma that separates each token, so let's split on that.
Let tokens equal input.split(",").

NOTE: If you want to preserve your input as a String , then don't do this step.

Parse your data, removing "GOOF" as you see it. You can use the String.replaceAll() for that.

for every token in tokens
    let token equal token.replaceAll("GOOF", nothing).

NOTE : If GOOF can come in different cases, it's time for some regexp . This is called a metalanguage , and it's designed to analyse and manipulate String s. What you want to do, is not take case into account, and you can achieve this using the ?i operator.

String regex = "(?i)GOOF";
String parsedInput = input.replaceAll(regex, "");
// And that's the only bit of Java you're getting!!

????

Profit! You have an array containing only the values, without GOOF appearing.