如何在GridView中打开一个链接的弹出窗口

Question

I am trying to build a pop-up window function in java script for my grid view and I cannot get the window to open up.

var oldgridcolor;
function SetMouseOver(element) {
    oldgridcolor = element.style.backgroundColor;
    element.style.backgroundColor = '#ffeb95';
    element.style.cursor = 'pointer';
    element.style.textDecoration = 'underline';
}
function SetMouseOut(element) {
    element.style.backgroundColor = oldgridcolor;
    element.style.textDecoration = 'none';

}
function SetMouseDown(element) {
    var r = confirm('Are you sure?');
    var url = window.location.pathname;
    var pathArray = url.split('/');
    var host = pathArray[1];
    var newHost = '/About.aspx';

    if (r == true) {
        window.location = host + newHost;
    }
    else {
        alert('it didnt work');
    }
    return false;
}

code behind

 protected void gvrecords_RowDataBound(object sender, GridViewRowEventArgs e)
  {
    if (e.Row.RowType == DataControlRowType.DataRow)
    {
        e.Row.Attributes["onmouseover"] = "javascript:SetMouseOver(this)";
        e.Row.Attributes["onmouseout"] = "javascript:SetMouseOut(this)";
        e.Row.Attributes["onmousedown"] = "javascript:SetMouseDown(this)";
    }

Any help would be very much appreciated.

Answer 1

Please try it, it may help you.

function SetMouseDown(element) {
    var r = confirm('Are you sure?');
    var url = window.location.pathname;
    var pathArray = url.split('/');
    var host = pathArray[1];
    var newHost = '/About.aspx';

    if (r == true) {
        //window.location = host + newHost;

        window.open(host + newHost,'name','width=200,height=200');
    }
    else {
        alert('it didnt work');
    }
    return false;
}