在xpath中选择评论的所有同级（包括文本）

Question

I have an XML document, a fragment line of which could look like this:

<p>Some text <!--a comment --> some more text <b>some bold text</b> something else etc</p>

I would like to select the comment based on its text, but also all following "sibling" elements. In this example, I know I can get the comment with '//comment()[. = "a comment"]'.

How can I get the result: " some more text something else etc"? (the remainder of the siblings inside the paragraph tag)

In case it makes any difference, I'm using python and etree to parse.

EDIT:

My test XML in full:

<?xml version="1.0" encoding="UTF-8"?>
<root>
<p>A paragraph<!--A comment--><b>test</b>A line break</p>
</root>

My test XSLT:

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
    version="1.0">
    <xsl:template match="/">
        <xsl:copy-of select='//comment()/following-sibling::node()'/>
    </xsl:template>
</xsl:stylesheet>

The result:

<?xml version="1.0" encoding="UTF-8"?>

or, in Python, using lxml, just a "None" object.

EDIT #2:

My bad -- the accepted answer works well!

Answer 1

If you want to get all siblings including other comments:

//comment()[.="a comment "]/following-sibling::node()

For example:

>>> xml.xpath('//comment()[.="a comment "]/following-sibling::node()')
[' some more text ', <Element b at 0x2923af0>, ' ', <!-- other comment -->, ' something else etc']

I added an additional comment but otherwise used your input data.