[英]How to join these rows into one record in the same table
the original data in table X表X中的原始数据
Date # Method # Count #
======================================
2012-08-24 # A # 44 #
2012-08-24 # B # 5 #
2012-08-24 # D # 1 #
*p/s there are total 8 methods which is a,b,c,d,e,f,g,h *p/s 共有 8 种方法,分别是 a、b、c、d、e、f、g、h
what I want to display is below :我要显示的内容如下:
Date # A # B # C # D # E # F # G # H #
2012-08-24 # 44 # 5 # 0 # 1 # 0 # 0 # 0 # 0 #
Try this:尝试这个:
SELECT A.Date,
SUM(CASE WHEN A.Method = 'A' THEN A.Count ELSE 0 END) AS 'A',
SUM(CASE WHEN A.Method = 'B' THEN A.Count ELSE 0 END) AS 'B',
SUM(CASE WHEN A.Method = 'C' THEN A.Count ELSE 0 END) AS 'C',
SUM(CASE WHEN A.Method = 'D' THEN A.Count ELSE 0 END) AS 'D',
SUM(CASE WHEN A.Method = 'E' THEN A.Count ELSE 0 END) AS 'E',
SUM(CASE WHEN A.Method = 'F' THEN A.Count ELSE 0 END) AS 'F',
SUM(CASE WHEN A.Method = 'G' THEN A.Count ELSE 0 END) AS 'G',
SUM(CASE WHEN A.Method = 'H' THEN A.Count ELSE 0 END) AS 'H'
FROM tableA A
GROUP BY A.Date
You can alternately use IF您可以交替使用 IF
SELECT
A.Date,
IF(A.Methos = 'A',A.Count,0) AS 'A',
IF(A.Methos = 'B',A.Count,0) AS 'B',
IF(A.Methos = 'C',A.Count,0) AS 'C',
IF(A.Methos = 'D',A.Count,0) AS 'D',
IF(A.Methos = 'E',A.Count,0) AS 'E',
IF(A.Methos = 'F',A.Count,0) AS 'F',
IF(A.Methos = 'G',A.Count,0) AS 'G',
IF(A.Methos = 'H',A.Count,0) AS 'H',
FROM tableA A
GROUP BY A.Date
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.