计算C中文本文件中单词的出现次数

Question

The following code is intended to find the occurrences of the word 'if' from a text file chosen by the user, however the result after exiting the loop is always 0. Question is how it could be possibly fixed.

#include<stdio.h>
#include<conio.h>
#include<string.h>
int main() {
    FILE * f;
    int count = 0, i;
    char buf[50], read[100];
    printf("Which file to open\n");
    fgets(buf, 50, stdin);
    buf[strlen(buf) - 1] = '\0';
    if (!(f = fopen(buf, "rt"))) {
        printf("Wrong file name");
    } else printf("File opened successfully\n");
    for (i = 0; fgets(read, 100, f) != NULL; i++) {
        if (read[i] == 'if') count++;
    }
    printf("Result is %d", count);
    getch();
    return 0;
}

Answer 1

1. 'if' isn't what you think it is; it's a multicharacter literal, not a string.

2. You can't compare strings with == in C. Use strcmp(3) .

3. Your loop doesn't look like it does what you want either; time to break out a debugger (and probably strtok(3) ).

Answer 2

Your if test is wrong.

if (read[i]=='if') /* no */

Use strcmp

if (strcmp(read[i], "if") == 0) /* check if the strings are equal */

Answer 3

For one thing, read[i] only contains a single character and will never be equal to any multi-character word.

For another, single apostrophe's are used to define single characters. 'if' is not a string of characters.

You will need to parse each line to find each individual word, and then compare each word to the target word using something like stricmp() .