SQL我想从时间表中选择时间，但检查未选中的其他表中的所有时间值

Question

here is the time table that I use

time "table"
---------------
1   |  07:00:00
2   |  08:00:00
3   |  09:00:00
4   |  10:00:00
5   |  11:00:00
6   |  12:00:00
7   |  13:00:00
8   |  14:00:00

these table is the one where I check the time must not be be select

sched_daytime "table"
---------------
Day          Start_time   End_time
-------------------------------------
Monday    |  07:00:00  | 08:00:00
Wednesday |  08:00:00  | 10:00:00
Monday    |  09:00:00  | 11:00:00

here is my sql query

select time.* 
from time,sched_daytime 
where time not between sched_daytime.s_time and sched_daytime.e_time 
AND sched_daytime.day = 'Monday' 
group by time.time

but the result is its still shows all time values in time table which suppose between 7:00 to 8:00 and 9:00 to 11:00:00 are not available time

its select all the values in time table please help sorry im still noob

Answer 1

尝试以下操作：从time，sched_daytime中选择时间，其中day ='Monday'并且时间不在start_time和end_time之间按时间分组