[英]Mysql JOIN subquery
How should I do query where 我应该如何查询
I would like to have all rows from table1 which have all rows column1 not as null or no rows at all, in table2. 我想让table1中的所有行都具有table2中的所有列column1不为null或根本没有任何行。
Of course the basic sql goes like: 当然,基本的sql是这样的:
SELECT table1.* FROM table1 JOIN table2 ON table2.id = table1.table2_id
But what comes next? 但是接下来呢?
You can count the occurences of null in your query like SUM(CASE WHEN table2.col IS NULL THEN 1 ELSE 0 END) AS nullcount
, i assume table2.col
is the one which has date of null in it 您可以像SUM(CASE WHEN table2.col IS NULL THEN 1 ELSE 0 END) AS nullcount
这样的查询来计算查询中null的出现, SUM(CASE WHEN table2.col IS NULL THEN 1 ELSE 0 END) AS nullcount
,我假设table2.col
是其中日期为null的那个
SELECT
table1.*,
SUM(
CASE
WHEN table2.col IS NULL
THEN 1
ELSE 0
END
) AS nullcount
FROM
table1
JOIN table2
ON table2.id = table1.table2_id
HAVING nullcount > 0
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