SimpleDateFormat解析时间

Question

i need to parse a String value and get it as date object. Am using the following snippet

  java.util.Date temp = new SimpleDateFormat("HH:mm:ss").parse("14:58:00");

My output is : Thu Jan 01 14:58:00 IST 1970

But what i need is only 14:58:00 as Date object is there any way to achieve this? If not what is the other way around? Please help.

EDIT I need this way because,

I have a Jspinner(in a Jpanel) for selecting time in HH:mm:ss format . The scenario is I will open the JPanel to select the time and click on save button so the values selected will be saved in a variable(x).Now if i open the Jpanel again the previously selected values should be shown which will be read from the variable(x).

For this am using following code,

    SpinnerModel Startmodel = new SpinnerDateModel();
    StarttimeSpinner = new JSpinner(Startmodel);
    Date date = new SimpleDateFormat("HH:mm:ss").parse("14:58:00");
    StarttimeSpinner.setValue(date);

On parse line am facing the problem. where i need only time(14:58:00) as date object.

NOTE: I have tried the below code( it will work but wont allow us to change value again)

    StarttimeSpinner = new JSpinner();
    Date time = new SimpleDateFormat("HHmmss", Locale.ENGLISH).parse("000000");
    SimpleDateFormat formatter = new SimpleDateFormat("HH:mm:ss");
    String dateString = formatter.format(time);
    StarttimeSpinner.setModel(new SpinnerListModel(new String[]{dateString}));

Answer 1

您可能想使用new SimpleDateFormat("HH:mm:ss").formatDate(date) （可以使用相同的new SimpleDateFormat("HH:mm:ss").formatDate(date)实例）进行输出...