捕获组中的多个单词

Question

I am trying to parse something in Python where I have a string, a number, and then an undetermined amount of strings after the number. I would like to be able to put all the remaining strings (in this case "D e") into one group for processing later. This is the code I have:

m = re.match(r"(\w+) (\w+) (*)", "de 2166 D e")

What should I be doing to create a group of "D e"?

Answer 1

The code is missing . . ( . match any character except newline)

>>> m = re.match(r"(\w+) (\w+) (.*)", "de 2166 D e")
    #                           ^
>>> m.groups()
('de', '2166', 'D e')

If you want to extract only the 3rd group, use MatchObject.group :

>>> m.group(3)
'D e'

---

EDIT suggested by Joe Lewis:

Use following regular expression if you want to accept only digits for the second group. ( \\w -> \\d )

r"(\w+) (\d+) (.*)"
#         ^