如何读取以json格式从远程服务器发送的$ _POST字段？

Question

This is the code for the notification that I receive from the server that my work is complete. It returns a $_POST field, say xyx , in JSON format. I tried various combinations, even wrapping in json_decode , yet it returns NULL .

I also want to access a few values from the POST for further processing into database.

<?php
ini_set('display_errors', 'Off');
echo "notification is arriving ...";
sleep(2);

//echo $_POST['message'];
//print_r($_POST,true);

$json = file_get_contents("php://input");
$obj = json_decode($json);
var_dump($obj);  //CHECKING
?>

SAMPLE OUTPUT:

notification is arriving ...NULL

EDIT : AFter var_dump($_POST);

array(2) { ["xyw"]=> string(2262) "{"ok":"ASSEMBLY_COMPLETED","message":"The assembly was successfully completed.","....and the rest of json output .

After var_dump("php://input")

string(11) "php://input" .. If I remove quotes..nothing. Blank page .

Answer 1

The following line:

$json = file_get_contents("php://input");

Will return an ARRAY, not a json object. Thus, the following line:

$obj = json_decode($json);

is trying to decode an array, and it will fail (because the type of $json is Array and not an json object.

Hope this answers your question.

EDIT

If you want your script to return a json object, you should use json_encode instead and then echo it.

EDIT2

To read, just do as follows:

$json = file_get_contents("php://input");
$myVar1 = $json['xyw'];
echo $myVar1;

EDIT3

I've seen the output you have pasted and I see that it is a json string, you could encode it as follows:

$post= file_get_contents("php://input");
$json = json_encode($post['xyw']);

Hope this helps.