Python：在一行中优雅地打印列表中的所有*剩余*元素

Question

I'm looking for the most correct way to print a list of elements after replacing one of them. I could do as follows but it's obviously messy.

#!/usr/bin/python

import sys

file = open(sys.argv[1])

for line in file:
    cols = line.split('\t')

    if(float(cols[2]) > 97):
        print line
    else:
        print cols[0] + "\tNo_Match\t" + cols[2] + "\t" + cols[3] + "\t" + cols[4] + "\t" + .....  + "\t" +cols[20]

EDIT: I just realised it would be even worse because I missed out the + "\\t"

Answer 1

This gives identical behavior to the last line of your code:

print cols[0] + "\tNo_match\t" + ''.join(cols[2:])

To match the revised version of your code:

print cols[0] + "\tNo_match\t" + '\t'.join(cols[2:])

Answer 2

You could use the join method of a string to print your list:

cols[1] = "No_Match"
print '\t'.join(cols)

This will print off all entries of cols separated by a '\\t'.

Notice how I replaced the element 1 of cols first. If you don't want to do that, you can do either

print '\t'.join(cols[0:1]+['No_Match']+cols[2:])

or

print '\t'.join([x if i != 1 else 'No_Match' for i, x in enumerate(cols)])