用户事件表中一天的MYSQL'SELECT'和COUNT个“活动”用户

Question

+----+--------------+------------+--------+
| id | user    | date(data) | type        |
+----+--------------+------------+--------+
|  3 | 5458848 | 2013-12-19 | SUBSCRIBE   |
|  4 | 5458848 | 2013-12-19 | UNSUBSCRIBE |
|  5 | 5458848 | 2013-12-20 | SUBSCRIBE   |
|  7 | 5458848 | 2013-12-20 | UNSUBSCRIBE |
|  8 | 7883870 | 2013-12-20 | SUBSCRIBE   |
|  9 | 7883870 | 2013-12-23 | UNSUBSCRIBE |
| 10 | 7883870 | 2013-12-24 | SUBSCRIBE   |
| 11 | 7883870 | 2013-12-24 | UNSUBSCRIBE |
| 12 | 7883870 | 2013-12-24 | SUBSCRIBE   |
+----+---------+------------+-------------+                                                 

Hello, I need to know how make query in mysql for watch how many users have active and not-active daily,

example: if one user is SUBSCRIBE and UNSUBSCRIBE in the same day, it mean that for that day, I have a user not-active

+------------+-------------+-------------+
| date(data) | active      | inactive    |
+------------+-------------+-------------+
| 2013-12-19 | 0           | 1           |
| 2013-12-20 | 1           | 1           |
| 2013-12-23 | 0           | 2           |
| 2013-12-24 | 1           | 1           |
+------------+-------------+-------------+

Answer 1

Try this...

SELECT SUM(CASE WHEN type='SUBSCRIBE' THEN 1 ELSE 0 END) as active,
       SUM(CASE WHEN type='UNSUBSCRIBE' THEN 1 ELSE 0 END) as inactive
WHERE (date>='2013-12-19' and date<='2013-12-24');

Answer 2

You need the difference between the cumulative number of subscribes and unsubscribes on each date in order to calculate whether someone has subscribed or not. For example, the last user 7883870 has a state of "subscribe" after three events on the same day.

One way to do this is with correlated subqueries:

select t.user, t.date,
       (select sum(type = 'SUBSCRIBE') - sum(type = 'UNSUBSCRIBE')
        from table t2
        where t2.user = t.user and
              t2.date <= t.date
       ) netsubs
from table t
group by t.user, t.date;

WIth this information, we can then determine the state someone is in on a given date.

select date, 
       sum(case when netsubs > 0 then 1 else 0 end) as active,
       sum(case when netsubs = 0 then 1 else 0 end) as inactive
from (select t.user, t.date,
             (select sum(type = 'SUBSCRIBE') - sum(type = 'UNSUBSCRIBE')
              from table t2
              where t2.user = t.user and
                    t2.date <= t.date
             ) netsubs
      from table t
      group by t.user, t.date
     ) t
group by t.date;

EDIT:

I misunderstood the question. On any given day, you want the number of users that are active or have unsubscribed up to that point.

select date, numacive, numusers - numactive as numinactive
from (select date,
             (select count(distinct user)
              from table t2
              where t2.date <= t.date
             ) as numusers,
             (select sum(type = 'SUBSCRIBE') - sum(type = 'UNSUBSCRIBE')
              from table t2
              where t2.date <= t.date
             ) as numactive
      from (select distinct date
            from table t
           ) t
     ) t;

Answer 3

set @ac:=null;
DROP TABLE IF EXISTS ___active_nums;

CREATE TABLE ___active_nums(
  event_id integer,
  event_user_id integer,
  event_date  Date,
  number_of_active_users integer,
  INDEX USING BTREE (event_date)
)
ENGINE=MEMORY 
;

INSERT INTO ___active_nums

SELECT

  events.id,
  events.user,
  events.date,
  ifnull( @ac:= ( @ac + if( type='SUBSCRIBE', 1, -1) ), @ac:=if( type='SUBSCRIBE', 1, -1) ) AS active_num

FROM 
(
  SELECT * FROM events ORDER BY id
)
AS events
;

SELECT

event_date as date,
number_of_active_users,

( SELECT count(DISTINCT event_user_id) FROM ___active_nums WHERE ___active_nums.event_date <= outer_active_nums.event_date )
- number_of_active_users
as number_of_inactive_users

FROM ___active_nums  AS outer_active_nums

WHERE event_id IN ( SELECT max(event_id) FROM ___active_nums GROUP BY event_date );