如何在长整数后附加字符？

Question

I want to append a character to a long integer, using the below code:

if (strArrIds[1].Contains("CO"))
{
    long rdb2 = Convert.ToInt64(strArrIds[1].Substring(strArrIds[1].Length - 1));
    assessmentEntity.RatingType = rdb2;
}

If rdb2 = 5 , I want to append a L to this value, like rdb2 = 5L .

Any ideas? Thanks in advance.

Answer 1

You can using Long.Parse instead Convert.ToInt64 to get the long and you wont need to append L to make it long

if (strArrIds[1].Contains("CO"))
{
    long rdb2 = long.Parse(strArrIds[1].Substring(strArrIds[1].Length - 1));
    assessmentEntity.RatingType = rdb2;
}

Answer 2

If you are processing a lot of these, and if this item will be used for further processing, you could consider turning this into a class which might be easier to manage. This would also allow you to more easily customise your ratings.

I'm thinking maybe a factory might serve you well also which could instantiate and return your assessment entity. You could then leverage a dependency injection strategy for any other functionality.

Its a little hard to tell what you require this for without a bit more context.

If this is a once off, I would refactor to

assessmentEntity.RatingType = strArrIds[1].Contains("CO") ? 
          String.Concat(long.Parse(strArrIds[1].Substring(strArrIds[1].Length - 1)).ToString(), "L") :
          "0N";

Assuming "0N" is some other default rating..

Answer 3

You do not need an L here. That is only for literals of type long appearing in the C# source.

You could do something like:

string str1 = strArrIds[1];
if (str1.Contains("CO"))
{
    long rdb2 = str1[str1.Length - 1] - '0';
    if (rdb2 < 0L || rdb2 > 9L)
      throw new InvalidOperationException("Unexpected rdb2 value from str1=" + str1);
    assessmentEntity.RatingType = rdb2;
}