未捕获到的SyntaxError：意外令牌：

Question

i have an unexpected token : but i dont know why this is.

the code where it is happening.

<script type="text/javascript">
$('.delete-btn').click(function() {
 $.ajax(function() {
    type: 'POST',
    url: 'ajax.php',
    data: { filename: filename },
    success: function(return) {
        if(return == 'SUCCESS') {
            $this = $(this).closest('tr');
            $this.remove();
        }
    }
});
});
</script>

I hope someone can find why i get the unexpeded token : at the url: 'ajax.php', rule.

Answer 1

The syntax error is in your success callback. You've named the argument return , which is a reserved word. Call it something else.

---

Niet here, merging my answer into this one to complete the picture:

Change:

$.ajax(function() {

To:

$.ajax({

Pay closer attention to what you're writing :p

Answer 2

return is a reserved word in JavaScript. Use any other name other than return. I have used data instead of return. Also there is type is an error in ajax function you have written. updated the same. Use the below code

<script type="text/javascript">
$('.delete-btn').click(function() {
 $.ajax({
    type: 'POST',
    url: 'ajax.php',
    data: { filename: filename },
    success: function(data) {
        if(data == 'SUCCESS') {
            $this = $(this).closest('tr');
            $this.remove();
        }
    }
});
});
</script>

Answer 3

return is a keyword at javascript dont use it as a variable name

 <script type="text/javascript">
    $('.delete-btn').click(function() {
     $.ajax(function() {
        type: 'POST',
        url: 'ajax.php',
        data: { filename: filename },
        success: function(data) {
            if(data== 'SUCCESS') {
                $this = $(this).closest('tr');
                $this.remove();
            }
        }
    });
    });
    </script>