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使用C ++ 11 std :: thread获取segfault

[英]Getting segfault using c++11 std::thread

static T MultiplyElement(const Matrix& matrixA, const Matrix& matrixB, 
    unsigned M2col, unsigned M1row)
{
    T sumToReturn = 0;

    for (unsigned iM1colM2row = 0; iM1colM2row < matrixA.m_n; iM1colM2row++)
    {
        sumToReturn += 
            matrixA.m_data[M1row][iM1colM2row] * matrixB.m_data[iM1colM2row][M2col];
    }

    return sumToReturn;
}

... ...

    std::vector<std::thread> threads;
    for(unsigned i = 0; i < outM ; ++i)
    {
        for(unsigned j = 0; j < outN; ++j)
        {
            threads.push_back(std::thread([&]()
            {
                outMatrix.m_data[i][j] = MultiplyElement(matrixA, matrixB, i, j);
            }
            ));
        }
    }
    for(auto& thread : threads)
    {
        thread.join();
    }

Compiled with: clang++ -std=c++11 -stdlib=libc++ newFile.cpp 编译:clang ++ -std = c ++ 11 -stdlib = libc ++ newFile.cpp

I'm getting a segfault in MultiplyElement... any idea why? 我在MultiplyElement中遇到段错误...为什么知道?

I think the problem is with your capture. 我认为问题出在您的捕获上。 You are using reference-capture for all variables. 您正在对所有变量使用引用捕获。 You should be capturing i and j by value. 您应该按值捕获ij Try [&, i, j] for your capture clause. 尝试使用[&, i, j]作为您的捕获子句。

Edit: You can check the answer here . 编辑:您可以在此处检查答案 You have the same issue. 你有同样的问题。

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