从另一个带有命令行参数的Python脚本中打开IDLE

Question

I am looking to open a Python script in edit mode in IDLE by passing in a directory from another Python script. I understand that I can use os.system to execute idle.py but I then don't know how to pass the appropriate -e parameter and get it to use a specific directory ie open something.py in diredtory C:\\Python all from the original Python script.

Thanks for your help,

Ben

Answer 1

You can use subprocess.call() . By setting shell = True , the function treats the string as a literal shell command. Modify the paths as you see fit.

import subprocess

subprocess.call(r'C:\Python27\Lib\idlelib\idle.py -e C:\Python27\something.py',
                shell=True)