在Python中将秒转换为星期几小时几分秒

Question

I'm trying to code a Python script for 'Enter the number of Seconds' and get results in weeks, days, hours, minutes and seconds. Here is what I have, but I am not getting the correct answers. What am I doing wrong?

seconds = raw_input("Enter the number of seconds:")
seconds = int(seconds)

minutes = seconds/60

seconds = seconds % 60

hours = minutes/60
hours = seconds/3600

minutes = minutes % 60

days = hours/24
days = minutes/1440
days = seconds/86400

hours = hours % 60
hours = minutes % 60
hours = seconds % 3600

weeks = days/7
weeks = hours/168
weeks = minutes/10080
weeks = seconds/604800

days = days % 1
days = hours % 24
days = minutes % 1440
days = seconds % 86400

weeks = weeks % 1
weeks = days % 7
weeks = hours % 168
weeks = minutes % 10080
weeks = seconds % 604800

print weeks, 'weeks', days, 'days', hours, 'hours', minutes, 'minutes', seconds, 'seconds'

Answer 1

Just from the basic conversion principles:

weeks = seconds / (7*24*60*60)
days = seconds / (24*60*60) - 7*weeks
hours = seconds / (60*60) - 7*24*weeks - 24*days
minutes = seconds / 60 - 7*24*60*weeks - 24*60*days - 60*hours
seconds = seconds - 7*24*60*60*weeks - 24*60*60*days - 60*60*hours - 60*minutes

A bit of a less noisy way of doing the same thing:

weeks = seconds / (7*24*60*60)
seconds -= weeks*7*24*60*60
days = seconds / (24*60*60)
seconds -= days*24*60*60
hours = seconds / (60*60)
seconds -= hours*60*60
minutes = seconds / 60
seconds -= minutes *60

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A cleaner version of again the same thing with divmod function which returns both division result and remainder in a tuple (division, remainder) :

weeks, seconds = divmod(seconds, 7*24*60*60)
days, seconds = divmod(seconds, 24*60*60)
hours, seconds = divmod(seconds, 60*60)
minutes, seconds = divmod(seconds, 60)

Basically, this solution is closest to your attempt since this is what divmod does:

weeks, seconds = divmod(seconds, 7*24*60*60)

equivalent to

weeks = seconds / (7*24*60*60)
seconds = seconds % (7*24*60*60)

Here we are essentially finding the number of whole weeks in our time and keeping what is left after these weeks are removed.

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And also you can go from the other end to make it even prettier:

minutes, seconds = divmod(seconds, 60)
hours, minutes = divmod(minutes, 60)
days, hours = divmod(hours, 24)
weeks, days = divmod(days, 7)

The idea behind this is that the number of seconds in your answer is the remainder after dividing them in minutes; minutes are the remainder of dividing all minutes into hours etc... This version is better because you can easily adjust it to months, years, etc...

Answer 2

Using Python's datetime timedeltas with support for milliseconds or microseconds.

import datetime
def convert(sec): 
    td = datetime.timedelta(seconds=sec, microseconds=sec-int(sec)) 
    return td.days/7, (td.days/7)%7, td.seconds/3600, (td.seconds/60)%60, td.seconds%60, td.microseconds, td.microseconds/1000

seconds = 8*24*60*60 + 21627.123  # 8 days, 6 hours (21600 seconds), 27.123 seconds
w, d, h, m, s, us, ms = convert(seconds)
print '{}s / {}w {}d {}h {}m {}s {}us {}ms'.format(seconds,w,d,h,m,s,us,ms)

712827.123s / 1w 1d 6h 0m 27s 123000us 123ms

Answer 3

def humanize_duration(amount, units='s'):
INTERVALS = [(lambda mlsec:divmod(mlsec, 1000), 'ms'),
             (lambda seconds:divmod(seconds, 60), 's'),
             (lambda minutes:divmod(minutes, 60), 'm'),
             (lambda hours:divmod(hours, 24), 'h'),
             (lambda days:divmod(days, 7), 'D'),
             (lambda weeks:divmod(weeks, 4), 'W'),
             (lambda years:divmod(years, 12), 'M'),
             (lambda decades:divmod(decades, 10), 'Y')]

for index_start, (interval, unit) in enumerate(INTERVALS):
    if unit == units:
        break

amount_abrev = []
last_index = 0
amount_temp = amount
for index, (formula, abrev) in enumerate(INTERVALS[index_start: len(INTERVALS)]):
    divmod_result = formula(amount_temp)
    amount_temp = divmod_result[0]
    amount_abrev.append((divmod_result[1], abrev))
    if divmod_result[1] > 0:
        last_index = index
amount_abrev_partial = amount_abrev[0: last_index + 1]
amount_abrev_partial.reverse()

final_string = ''
for amount, abrev in amount_abrev_partial:
    final_string += str(amount) + abrev + ' '
return final_string