如何在 sql server 2008 中获取一周的第一天和一周的最后一天？

Question

How to get the first day of the week and last day of the week when we input any one day of a week?

For example if we enter a date then the first(Monday) and last (Friday) day should be displayed. that is if we enter 24-jan-2014 then 20-jan-2014 and 24-jan-2014 should be displayed.

Regards

Answer 1

Here's how you can do it:

DECLARE @yourdate date = getdate()
Select dateadd(ww, datediff(ww, 0, @yourdate), 0)
Select dateadd(ww, datediff(ww, 0, @yourdate), 4)

You set @yourdate to the date you want. The first SELECT will give you the first day and the second SELECT will give you the last date

Answer 2

Try this

SELECT DATEADD(wk, DATEDIFF(wk, 6, '5/13/2005'), 6)
SELECT DATEADD(wk, DATEDIFF(wk, 5, '5/13/2005'), 5)

(Or)

Declare @Date datetime
Det @Date = '2012-04-12'
Delect @Date - DATEPART(dw, @Date) + 1 FirstDateOfWeek,
       @Date + (7 - DATEPART(dw, @Date)) LastDateOfWeek

Answer 3

这解决了它，并在年末结束：

SELECT DATEADD(wk, DATEDIFF(d, 0, '01 January 2017') / 7, 0)

Answer 4

With a calendar date already loaded, group can be done like this for all the years existing in the table =)

select 
Y,
M,
(Select dateadd(ww, datediff(ww, 0, dt), 0) ) wk_str_dt ,
(Select dateadd(ww, datediff(ww, 0, dt), 4)  )wk_end_dt , 
dt recd_crt_dt
from [tcalendar]
where  isWeekday= 1 
AND DW = 2 -- only mondays
order by Y, W