如何在每个子列表的索引[0]处拆分字符串，并将每个拆分索引放在它自己的原始列表中？

Question

How could you split a string at index 0 of all sublists into separate elements, and have each of the split elements be contained within a copy of the original sublist?

For example:

Original_List = [['a,b','c','d','e','f'],['1','2','3'],['z,y','1','2']]

Desired Result:

Desired_List = [['a','c','d','e','f'],['b','c','d','e','f'],['1','2','3'],['z','1','2'],['y','1','2']]

Also, to add further clarity with one more actual example:

Original_List = [['Contract_ID1,Contract_ID2','Amount','Date'],['Contract_ID3,Contract_ID4','400','Jan1']]

I want every sublist to have only one Contract_ID, but still have the Amount and Date Associated with it

Desired_List =  [['Contract_ID1','Amount','Date'],['Contract_ID2','Amount','Date'],['Contract_ID3','400','Jan1'],['Contract_ID4','400','Jan1']]

I can split all strings at index 0 of all sublists with the below, but I can't figure out how I would duplicate the whole list for each split element and then replace the strings that were split with the split element, so that each split element had its own list.

Split_First_Indices_of_Sublists = map(lambda x: x[0].split(","),Original_List)
>>[['a', 'b'], ['1'], ['z', 'y']]
for x in Original_List:
     x.pop(0)
>> [['c', 'd', 'e', 'f'], ['2', '3'], ['1', 2]]

Answer 1

I think it's clearest written out as explicit loops:

Desired_List = []

for li in Original_List:
    for spl in li[0].split(','):
        Desired_List.append([spl] + li[1:])

gives:

Desired_List
Out[153]: 
[['a', 'c', 'd', 'e', 'f'],
 ['b', 'c', 'd', 'e', 'f'],
 ['1', '2', '3'],
 ['z', '1', '2'],
 ['y', '1', '2']]

And of course you can immediately turn this into the equivalent one-line list comp:

[[spl] + li[1:] for li in Original_List for spl in li[0].split(',')]

Which may or may not be less readable, depending on the reader :-)

And as a last note, make sure that this is the data structure you really want. A dict keyed by Contract_ID seems like a very natural structure for your end product.

Answer 2

Original_List=[['a,b','c','d','e','f'],['1','2','3'],['z,y','1','2']]
desired_list=[]
for p in pl:
    try:
        splited=p.split(',')
        if not type(splited) is list:
            splited=[splited]
        if count(splited)>1:
            for list in splited:
                p[0]=list
                desired_list.append(p)
        else:
            desired_list.append()
    except:
        pass