[英]How can I target every n-th element in a list but only after 3
How can I write a formula for this expression: 如何为该表达式编写公式:
boolean showAd = (position == 3 || position == 11 || position == 19 || position == 27 || position == 35 || position == 43|| position == 51);
if (showAd) {.....
I tried position % 8 ==0
but this doesnt produce the same sequence as above 我尝试
position % 8 ==0
但这不会产生与上述相同的序列
Replace 更换
position % 8 ==0
by 通过
position % 8 == 3
The line 线
boolean showAd = (position == 3 || position == 11 ||
position == 19 || position == 27 || position == 35
|| position == 43|| position == 51);
will be similar to 将类似于
boolean showAd = (position - 3) % 8 == 0 // Note the parentheses
// (3 - 3) = 0 % 8 = 0
// (11 - 3) = 8 % 8 = 0
// (19 - 3) = 16 % 8 = 0
// (27 - 3) = 24 % 8 = 0
// ...
But is not necessary to store the boolean value in a separate variable (unless you will use it later): 但是没有必要将布尔值存储在单独的变量中(除非稍后使用):
if ((position - 3) % 8 == 0) {
...
}
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.