AdapterView是原始类型。 泛型类型AdapterView的引用 <T> 应该参数化

Question

my code showing this error...AdapterView is a raw type. References to generic type AdapterView should be parameterized for the AdapterView, what should i do?

public void onItemClick(AdapterView adapterview, View view, int i, long l) //*AdapterView is a raw type. References to generic type AdapterView<T> should be parameterized 
{
    ((ImageView)b.findViewById(0x7f090000)).setImageResource(a.getResources().obtainTypedArray(0x7f050000).getResourceId(i, -1));
    ((Button)b.findViewById(0x7f090002)).setOnClickListener(new c(this, b));
    ((Button)b.findViewById(0x7f090003)).setOnClickListener(new d(this, i));
    String s = a.getIntent().getAction();
    if ("android.intent.action.GET_CONTENT".equals(s) || "android.intent.action.PICK".equals(s))
    {
        ((Button)b.findViewById(0x7f090004)).setOnClickListener(new e(this, i, b));
    }
    b.show();
}

Answer 1

This is because this AdapterView is probably parametrized, which means that in its implementation the type is not forced, for example, to String or whatever else, but it's defined by the user.

So basically what the warning (not error) is telling you that instead of AdapterView adapterview you have to set it to AdapterView<YourType> adapterview (so you'd need to put here the type you've defined the AdapterView in the declaration.