[英]C++ - Copying unsigned char* to a new unsigned char* array
This is a followup question to to the question I posted here , although it different enough to warrant posting a new question. 这是我在这里发布的问题的后续问题,尽管它有足够的不同以保证发布新问题。
I have a OpenCV
( cv::Mat
) matrix variable (which is just an unsigned char *
of with a known size). 我有一个
OpenCV
( cv::Mat
)矩阵变量(它只是一个已知大小的unsigned char *
)。 I used the answer in the referenced question to copy a std::string
to my unsigned char*
array using the code: 我使用引用的问题中的答案使用代码将
std::string
复制到我的unsigned char*
数组:
int initial_offset = 10;
unsigned char *r_record = new unsigned char[1024]();
std::copy(title.begin(), title.end(), r_record + initial_offset);
This works as expected. 这按预期工作。 But now I would like to loop through each row of the
cv::Mat
variable and insert those unsigned char values into the same r_record
array. 但是现在我想循环遍历
cv::Mat
变量的每一行,并将那些unsigned char值插入到同一个r_record
数组中。
I have the code: 我有代码:
int data_offset = TITLE_OFFSET + 1;
cv::Mat &img = <from somewhere else>
for (int row=0; row<=img.rows; row++) {
unsigned char* i_row = img.row(row).data;
std::copy(???, ???, r_record + data_offset);
data_offset += img.cols; //This happens to be += 32 in every case that I am using
}
But I'm not sure what goes in place of the ???
但我不知道是什么代替
???
to reference the i_row
data. 引用
i_row
数据。 Can this be done? 可以这样做吗?
Also, apparently using new unsigned char[1024]()
is a bad idea, but I'm not sure how to replace it with something not bad. 此外,使用显然是
new unsigned char[1024]()
是一个坏主意,但我不知道如何用不坏的东西取代它。
Update: 更新:
Looks like the response from @juanchopanza below isn't quite working. 看起来下面@juanchopanza的回复不太合适。 Here is what I have:
这是我有的:
std::string = "Title 1";
cv::Mat mat = <from somewhere else>;
//Test case
desc.data[1] = (unsigned char)65;
//Write the image information to the database
unsigned char *image_record = new unsigned char[1024]();
std::copy(title.begin(), title.end(), r_record + title_offset);
std::copy(mat.begin<unsigned char>(), mat.end<unsigned char>(), r_record + 33);
But no matter what, r_record
only contains: "Title 1"
. 但无论如何,
r_record
只包含: "Title 1"
。 Does anyone have any ideas? 有没有人有任何想法?
像这样的东西:
std::copy(img.begin<unsigned char>(), img.end<unsigned char>(), r_record + data_offset);
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.